Answer:
The correct option is C. either a t test or an analysis of variance can be performed.
Step-by-step explanation:
Consider the provided information.
- The t-test, is used for whether the means of two groups are equal or not. The assumption for the test is that both groups are sampled from normal distributions with equal variances.
- Analysis of Variance (ANOVA) is a statistical method evaluating variations between two or more methods. ANOVA is used in a study to analyze the gaps between group methods.
- ANOVA is used not for specific differences between means, but for general testing.
- The chi-squared test is often used to evaluate whether there was a significant difference in one or more groups between the predicted frequencies and the observed frequencies.
Hence, Either a t test or an analysis of variance can be performed to determine whether the means of two population are equal.
Therefore, the correct option is C. either a t test or an analysis of variance can be performed.
Answer:
Hello!
After reading your question I have calculated the correct answer to be:
47.22
Step-by-step explanation:
The way I solved this equation was I first split the equation into two parts.
I took the two whole numbers, being "34" and "12", and made their own equation:
"34+12=?"
And then I took the two partial numbers "0.98" and "0.24" and made their own equation:
"0.98+0.24=?"
I then solved both equations:
"34+12= 46"
"0.98+0.24= 1.22"
And added those two solutions together to come up with the final solution:
"46+1.22= 47.22"
Hope this helped!
SOLUTION:
A normal distribution would model this situation because the distribution is approximately symmetrical, thus the mean, median and mode are approximately the same and the population size is large ( greater than 30).
Answer: 75%
Step-by-step explanation:
15/20 = 3/4 or 75%
Answer: JL = 25
Step-by-step explanation: Segment JM is the total measure of the line segment and it equals 45.
Suppose first segment JK measures d.
The total ratio is the sum of each part
d + 4d + 4d = 9d
The sum of each part corresponds to the total measure of the line segment. Then:
9d = 45
d = 5
Segment JL is
JL = d + 4d
JL = 5d
JL = 5.5
JL = 25
Segment JL measures 25 units.
