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Papessa [141]
1 year ago
8

Find the total surface area of the triangular prism.

Mathematics
1 answer:
Montano1993 [528]1 year ago
4 0

Answer:

\mathsf {480 cm^{2}}

Step-by-step explanation:

\textsf {Apply the Pythagorean Theorem to find missing edge length :}

\implies \mathsf {x^{2} = 13^{2} - 12^{2}}

\implies \mathsf {x^{2} = 169 - 144}

\implies \mathsf {x = \sqrt{25}}

\implies \mathsf {x = 5}

\textsf {Now, the total surface area is :}

\implies \textsf {Area of 2 right triangles + Area of base + Area of left slanted face}\\\textsf {+ Area of right slanted face}

\implies \mathsf {2 \times 1/2 \times 5 \times 12 + 13 \times 15 + 12 \times 15 + 5 \times 15}

\implies \mathsf {60 + 195 + 180 + 75}

\implies \mathsf {225 + 255}

\implies \mathsf {480 cm^{2}}

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19 A triangle has coordinate points at A 1, 3) B(3, 6) and C(3, 3). What is distance between of AC? (8 Points)​
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3 0
3 years ago
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4 0
3 years ago
Please help ❗️❗️❗️❗️ Please! I will reward brainly
zhuklara [117]
Hey there :)

We know the distance formula is:
D = \sqrt{(x2-x1)^2+(y2-y1)^2}

1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
                                    ↓   ↓       ↓    ↓
                                    x₁ y₁     x₂   y₂
We plug in the values 
D =\sqrt{(8 -(-10))^2+(5-(-5))^2}
    ≈20.59 ≈ 20.6 (nearest tenth)

We do the same for the rest

2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
D = \sqrt{(-2-10)^2+(1-0)^2}
   ≈ 12.04 ≈ 12.0 (nearest tenth)

3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
D = \sqrt{((7-4)^2+(-8-8)^2}
   ≈ 16.27 ≈ 16.3 (nearest tenth)

4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
D = \sqrt{(8-(-10))^2+(8-(-4))^2}
    ≈ 21.6 (nearest tenth)

5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D = \sqrt{(-8-6)^2 + (9-(-3))^2}
   ≈ 18.4 (nearest tenth) 

You can find the matching below :)



8 0
3 years ago
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