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3 years ago

You increase the size of a computer screen display by 20 %

Mathematics

2 answers:

Dvinal [7]3 years ago

6 0

Answer:

smaller than the size you started with

Step-by-step explanation:

Eva8 [605]3 years ago

4 0

Assuming display of computer is at 100%
So increase by 20% = 120 (20/100 *100)
then 20% of 120 is: 20/100 * 120 = 24

So the display is now 120-24 = 96

Hope this helps!

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Can someone please help me with this

Anuta_ua [19.1K]

Answer:

Perimeter = 18m

Area = 18m²

Step-by-step explanation:

On a rectangle, opposite sides have equal lengths. This means to find the perimeter you would do (3 × 2) + (6 × 2) which is 6 + 12 = 18

The perimeter is 18m

To find the area, you would do length × width. The length is 6 and the width is 3 so 6 × 3 is 18

The area is 18m²

Hope this helps!

4 0

2 years ago

Interior and Exterior Triangle Angles (0/5)

sweet-ann [11.9K]

Answer:

Step-by-step explanation:

<h2>Angle sum property</h2>

Sum of all angles of triangle = 180

5x - 11 + 3x - 3 + 3x + 18 = 180

5x + 3x + 3x -11 - 3 + 18 = 180

Combine like terms

11x + 4 = 180

11x = 180 - 4

11x = 176

x = 176/11

x = 16

∠R = 5x - 11

= 5*16 - 11

= 80 - 11

= 69

8 0

2 years ago

Which of the following equations have no solutions? Choose all answers that apply:

Marianna [84]

Answer:

All

Step-by-step explanation:

3 0

2 years ago

Anthony has a bag that contains 4 blue candies, 6 green candies, and 10 yellow candies. * Without looking, he pulls out a piece

BigorU [14]

Answer:

0.03

Step-by-step explanation:

6 0

3 years ago

Suppose that start-up companies in the area of biotechnology have probability 0.2 of becoming profitable, and that those in the

schepotkina [342]

Answer:

a) 0.03

b) 0.68

c) 0.32

Step-by-step explanation:

We are given the following in the question:

B: companies in the area of biotechnology

I: companies in the area of information technology

P(B) = 0.2

P(I) = 0.15

The two events are given to be independent.

a) P(both companies become profitable)

$P(B\cap I) = P(B)\times P(I)\\= 0.2\times 0.15 = 0.03$

0.03 is the probability that both companies become profitable

b) P(neither company becomes profitable)

$P(B'\cap I')\\=P(B')\times P(I')\\=(1-P(B))(1-P(I))\\=(1-0.2)(1-0.15)\\=0.68$

0.68 is the probability that neither company becomes profitable.

c) P(at least one of the two companies become profitable)

$P(B\cup I) = P(B) + P(I) - P(B\cap I)\\= 0.2 + 0.15 - 0.03\\=0.32$

0.32 is the probability that at least one of the two companies become profitable

4 0

3 years ago