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Ket [755]
4 years ago
10

Classify the triangle with angles measuring 120°, 40°, and 20°.

Mathematics
1 answer:
N76 [4]4 years ago
8 0
<span>Scalene triangles;


is  this  multiple choice or is it a written question?</span><span /><span>
</span>
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For the equation x/3=15 a student found the value of x to be 5.explain the error
egoroff_w [7]
Let plug the variable into the equation.

x = 5
5/3=15

We can conclude that this is incorrect because 5/3 does NOT equal 15

The correct answer would be: 15/3 = 5; 15/5=3; or
 3(5) = 15 or 45/3=15

All 4 of these are correct answers. 
5 0
3 years ago
Read 2 more answers
How do you solve this equation ( ASAP PLS )
makvit [3.9K]
<span>Solve this by substitution:

</span>Solve 5x - 4y = -13 for x:<span><span><span><span>5x </span>− <span>4y </span></span>+ <span>4y </span></span>= -<span>13 + <span>4y     </span></span></span>(Add 4y to both sides)
<span><span><u>5x  </u></span>= <span><span><u>4y - </u><u>13 </u></span><u> </u>  </span></span>(Divide both sides by 5)
 5          5

<span>x = <span><span><span><u>4</u></span> y </span>+ -<span><u>13</u><span>
</span></span></span></span>      5        5
You can use https://www.mathpapa.com/algebra-calculator.html
5x - 4y = -13, 8x +10y = 12 (enter both equations with a comma between them and it will solve for you and show you step by step.


8 0
4 years ago
10/√149<br><br> PLZ HELP IVE BEEN STUCK ON THIS PROBLEM FOR AGES
sesenic [268]

Answer:

≈0.819232 or \frac{10\sqrt{149} }{149}

Step-by-step explanation:

\frac{10}{\sqrt{149}} times \frac{\sqrt{149} }{\sqrt{149} }

\frac{10\sqrt{149} }{149}

5 0
3 years ago
What is the right triangle definition of the cosecant function?
Basile [38]

Answer:

the cosecant of an angle is the length of the hypotenuse divided by the length of the opposite side.


4 0
3 years ago
Read 2 more answers
Find the measure of arc DC, in degrees, where the ? is shown. D ? 49° 70° с B​
bazaltina [42]

Answer:

m(arc CD) = 122°

Step-by-step explanation:

Since, measure of an arc = 2 × (Angle subtended by the arc at the circumference of the circle)

m(arc CD) = 2[m(∠CBD)]

By triangle sum theorem in ΔBCD,

m∠CBD + m∠BDC + m∠DCB = 180°

m∠CBD + 49° + 70° = 180°

m∠CBD = 180° - 119°

m∠CBD = 61°

Therefore, m(arc CD) = 2 × 61°

m(arc CD) = 122°

4 0
3 years ago
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