Question

Factor: 21x^3+6x^2+7x+2 I will give Brainliest to the first person :) please show all work

Answer 1

Answer:

(3x^2+1)*(7x-2)

Step-by-step explanation:

(1): "x2"   was replaced by   "x^2".  1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

 (((21 • (x3)) -  (2•3x2)) +  7x) -  2

STEP

2

:

Equation at the end of step

2

:

 (((3•7x3) -  (2•3x2)) +  7x) -  2

STEP

3

:

Checking for a perfect cube

3.1    21x3-6x2+7x-2  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  21x3-6x2+7x-2

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  7x-2

Group 2:  21x3-6x2

Pull out from each group separately :

Group 1:   (7x-2) • (1)

Group 2:   (7x-2) • (3x2)

              -------------------

Add up the two groups :

              (7x-2)  •  (3x2+1)