Answer:
(3x^2+1)*(7x-2)
Step-by-step explanation:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
(((21 • (x3)) - (2•3x2)) + 7x) - 2
STEP
2
:
Equation at the end of step
2
:
(((3•7x3) - (2•3x2)) + 7x) - 2
STEP
3
:
Checking for a perfect cube
3.1 21x3-6x2+7x-2 is not a perfect cube
Trying to factor by pulling out :
3.2 Factoring: 21x3-6x2+7x-2
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 7x-2
Group 2: 21x3-6x2
Pull out from each group separately :
Group 1: (7x-2) • (1)
Group 2: (7x-2) • (3x2)
-------------------
Add up the two groups :
(7x-2) • (3x2+1)
