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2 years ago

Factor: 21x^3+6x^2+7x+2 I will give Brainliest to the first person :) please show all work

Mathematics

1 answer:

Liula [17]2 years ago

3 0

Answer:

(3x^2+1)*(7x-2)

Step-by-step explanation:

(1): "x2" was replaced by "x^2". 1 more similar replacement(s).

STEP

Equation at the end of step 1

(((21 • (x3)) - (2•3x2)) + 7x) - 2

STEP

Equation at the end of step

(((3•7x3) - (2•3x2)) + 7x) - 2

STEP

Checking for a perfect cube

3.1 21x3-6x2+7x-2 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 21x3-6x2+7x-2

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 7x-2

Group 2: 21x3-6x2

Pull out from each group separately :

Group 1: (7x-2) • (1)

Group 2: (7x-2) • (3x2)

-------------------

Add up the two groups :

(7x-2) • (3x2+1)

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Shkiper50 [21]

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Step-by-step explanation:

Evaluating the linear rule given, for n = 1, we have ...

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_____

We suspect you may intend the exponential function ...

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Then, for n = 1, we have ...

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_____

When writing an exponential expression in plain text, it requires the exponential operator, a caret (^). If the exponent contains any arithmetic, as this one does, it must be enclosed in parentheses.

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