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Leno4ka [110]
3 years ago
8

Please please please help me !!

Mathematics
1 answer:
sweet [91]3 years ago
6 0
The ansewr is C. x<77


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If you vertically compress the absolute value parent function ?? What is the equation of the new function
Bumek [7]

Answer: Choice A -- f(x) = (1/3)*|x|

============================================

The input of a function is x and the output is y = f(x)

To vertically compress a function, we will multiply the y value by some fraction smaller than 1. This is so that the y coordinates are a fraction of what they once were.

In this case, we multiply y by 1/3 so that something that has a y coordinate of y = 81 becomes y = 27 (divide by 3)

So we have y = f(x) become (1/3)*y = (1/3)*f(x) = (1/3)*|x|

4 0
3 years ago
Write a unit rate for 53 pages in 2 hours
gulaghasi [49]

Answer: 26.5 pages/hr

Step-by-step explanation:

53 pgs/2 hours = 26.5 pages/hr

5 0
3 years ago
Line segment AB has endpoints A(0, 3) and B(2, 2). What is the midpoint of<br> line segment AB?
Anvisha [2.4K]
I think it would be b because if you use the midpt formula it’d turn out to be that ?
4 0
3 years ago
The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
3 years ago
Read 2 more answers
BIG IDEAS MATH<br> #9<br> i<br> Find the value of x.<br> 110x²<br> А.<br> 20x<br> X =
natka813 [3]
90 + 20x + 10x = 180
30x = 90
x = 3
6 0
2 years ago
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