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Neporo4naja [7]
2 years ago
5

Can you please tell me how to do this - with steps please? thank you! the topic is linear models.

Mathematics
2 answers:
Citrus2011 [14]2 years ago
6 0
7 because there will be some cans left at the 6 hours and 7 all will be gone.
Rus_ich [418]2 years ago
3 0
You take the total amount of cans (80) and divide it by the total amount of cans per hour so you would do 80/12
And that equals 6.666 or 6 2/3
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Solve the equation 6.6m= -117
marusya05 [52]

hope it will help u............

6 0
2 years ago
Find the inverse function of y=1
AveGali [126]

Answer:

To find the inverse, interchange the variables and solve for y

f^−1(x)=−7x+7

Hope I helped :)

4 0
2 years ago
Read 2 more answers
If 9a+5b+5c=9 what is -10c-18a-10b?
Rus_ich [418]
9a + 5b + 5c = 9

Multiplying the whole equation by -2.

-18a - 10b - 10c = -18.

Hence, the answer is -18.
6 0
3 years ago
If someone could help! ​
ad-work [718]

Step-by-step explanation:

This time round, use SOH method (Sin angle = Opposite/Hypotenuse)

given Opposite = 7

Hypotenuse = 10

\sin(x)  =  \frac{opposite}{hypotenuse}  \\  \sin(x)  =  \frac{7}{10}  \\ x =  {sin}^{ - 1} ( \frac{7}{10} ) \\  = 44.4deg(nearest \: tenth)

4 0
3 years ago
HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270
BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

  • sinθ = -4sqrt(17)/17 or A choice.
4 0
3 years ago
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