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3 years ago

Can you please tell me how to do this - with steps please? thank you! the topic is linear models.

Mathematics

2 answers:

Citrus2011 [14]3 years ago

6 0

7 because there will be some cans left at the 6 hours and 7 all will be gone.

Rus_ich [418]3 years ago

3 0

You take the total amount of cans (80) and divide it by the total amount of cans per hour so you would do 80/12
And that equals 6.666 or 6 2/3

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Select the correct description for the expression x+3/5

elena55 [62]

Answer:

the answer is A that's the answer

7 0

2 years ago

Mrs. Lopez cut 46 cm of yarn miss Hamilton cut 22 cm less than Miss Lopez how many centimeters of yarn does Miss Hamilton cut

Tcecarenko [31]

Answer: 24 cm

Step-by-step explanation:

Mrs Lopez cut 46cm of yarn.

Miss Hamilton then cut 22cm less than what Mrs Lopez had cut.

Mrs. Hamilton must have therefore cut:

This is a case of subtraction:

= 46 - 22

= 24 cm

5 0

3 years ago

Solve the Anti derivative.

Alex Ar [27]

Answer:

$\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C$

General Formulas and Concepts:

Algebra I

Factoring

Calculus

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$

Step 2: Integrate Pt. 1

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

Step 3: Identify Variables

Set up u-substitution for the arctan trig integration.

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

Step 4: Integrate Pt. 2

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$