Answer:
Hypotenuse: 100
Segment Adjacent to the leg: 36
x=60
Step-by-step explanation:
I submitted and it was correct
Answer:
Yes
Step-by-step explanation:
I had this exact question.
Answer:
An identity matrix, is a matrix that have '1' in the main diagonal. All of the other terms are '0'. When you multiply any matrix by the identity matrix, the result is the same matrix that you multiplied.
Example:
![\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D)
In the set of the real number is the same that the application of identity property.
Every number multiplied by 1 es the same number.
Step-by-step explanation:
20/3 - Take the 6 2/3, multiply the 6 and the 3 (6 x 3 = 18), then add the 2 (18 + 2 = 20). Put that number over the original 3 and you've got yourself a mixed number.
Answer: <em>10 + 9 </em>
Step-by-step explanation:
<em>1. Distribute: 3(6+3) - (8-x) = 18 + 9 - (8)</em>
<em>2. Eliminate redundant parentheses: 18 + 9 - (8) = 18 + 9 - 1 ⋅ 8</em>
<em>3. Multiply the numbers: 18 + 9 - 1 ⋅ 8 = 18 + 9 - 8 </em>
4. Combine like terms: 18 + 9 - 8 = 10 + 9
<em>⋅</em>
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