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blagie [28]
3 years ago
15

Which polynomial function has a leading coefficient of 3 and roots –4, i, and 2, all with multiplicity 1?

Mathematics
2 answers:
Goshia [24]3 years ago
6 0
The Answer is D. f(x) = 3(x<span> + 4)(</span>x<span> – </span>i)(x<span> + </span>i)(x<span> – 2)</span>
melomori [17]3 years ago
3 0

the answer really is d on e2020

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b(1 -2) i just too the test

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3 years ago
Which of the following correspondence is/are equivalent to TOP↔️SUN?
ArbitrLikvidat [17]

b.POT↔️NUS

Step-by-step explanation:

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3 years ago
Suppose the correlation coeffecient
Usimov [2.4K]

A relatively large correlation coefficient, such as the 0.87 given here, indicates a direct proportion relationship between two variables. Here, as baby gains weight, smart phone pricing increases. Note that this is NOT a causal relationship.

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3 years ago
A programmer plans to develop a new software system. In planning for the operating system that he will​ use, he needs to estimat
Vedmedyk [2.9K]

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A.  ​Yes, using the additional survey information from part​ (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

For this problem, we consider that we want it to be within 4%.

Item a:

  • The sample size is <u>n for which M = 0.04.</u>
  • There is no estimate, hence \pi = 0.5

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2

n = 600.25

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is \pi = 0.96, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}

\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2

n = 92.2

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to \pi = 0.5, the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151  

8 0
2 years ago
What does write two addition sentences where the sum is zero mean
Alex777 [14]
Pretty much, write two problems that equal to 0
6 0
3 years ago
Read 2 more answers
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