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3 years ago

Ten oranges cost $1.60. how much do 8 oranges cost?

Mathematics

1 answer:

aniked [119]3 years ago

7 0

Answer: $1.28 = cost of 8 oranges

Step-by-step explanation:

$1.60 / 10 = cost of 1 orange

$0.16 = cost of 1 orange

$0.16 (8) = cost of 8 oranges

$1.28 = cost of 8 oranges

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Help me out please!!!

AleksAgata [21]

1) side BD is common

2) angle ABD is equal to angle BDC (alternate angles)

3) angle CBD is equal to angle ADB (alternate angles)

5 0

3 years ago

Nella travelled 1/3 of a journey by bus, 2/3 of the remainder by bicycle and the remaining 9 km on foot. a)How far did Nella cyc

Kitty [74]

Answer:

18km

40.5km

Step-by-step explanation:

Let b = journey by bus

c = journey by bicycle

d = total journey

c = (2/3 x d) x 2/3

divide both sides by 2/s

c(3/2) = (2/3)d

c + 9km = 2/3d

c + 9km = 3/2 c

collect like terms and solve for c

3/2c - c = 9km

1/2c = 9km

c = 18km

2. IF cycling (18km) and walking (9km) make up 2/3 of the journey, 2/3 of the journey is 27km

2/3d = 27km

divide both sides by 3/2 to find d

d = 40.50 km

6 0

3 years ago

The length of a rectangle is five more than the width. The perimeter is 130cm. What is the area?

Evgen [1.6K]

<h2>Greetings!</h2>

Answer:

≅ 586.8

Step-by-step explanation:

Take x to be the width, if the length is 5x bigger than the width, then this can be shown by 5x.

The total perimeter is:

(2 * x) + (2 * 5x) because each side has another parallel one.

This means that 2x + 10x = 130

12x = 130

Divide both sides by 12:

$\frac{12x}{12} = \frac{130}{12}$

x = $\frac{65}{6}$

So the area = length * width

x * 5x = area

Substitute the values in:

$\frac{65}{6} * (5*\frac{65}{6})$ = 586.8055... ≅ 586.8

So the approximate area is 586.8

<h2>Hope this helps!</h2>

5 0

3 years ago

Show that only one n, n+2 and n+4 are divisible by 3

babymother [125]

N+2 divide 3 so it should be correct hope it helped

3 0

3 years ago

13. Write

Bingel [31]

First off, we factor out the expression:

$\displaystyle \large{y = 2 {x}^{2} - 12x + 16} \\ \displaystyle \large{y = 2 ( {x}^{2} - 6x + 8) }$

In the bracket, separate 8 out of the expression.

$\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 8)] }\\ \displaystyle \large{y = 2[ ( {x}^{2} - 6x) + 8]}$

In x^2-6x, find the third term that can make up or convert it to a perfect square form. The third term is 9 because:

$\displaystyle \large{ {(x - 3)}^{2} = {x}^{2} - 6x + 9}$

So we add +9 in x^2-6x.

$\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 9) + 8]}$

Convert the expression in the small bracket to perfect square.

$\displaystyle \large{y = 2[ {(x - 3)}^{2} + 8]}$

Since we add +9 in the small bracket, we have to subtract 8 with 9 as well.

$\displaystyle \large{y = 2[ {(x - 3)}^{2} + 8 - 9]} \\ \displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]}$

Then we distribute 2 in.

$\displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]} \\$

$\displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]} \\ \displaystyle \large{y = [2 \times {(x - 3)}^{2} ]+[ 2 \times ( - 1)] } \\ \displaystyle \large{y = 2 {(x - 3)}^{2} - 2 }$

Remember that negative multiply positive = negative.

Hence the vertex form is y = 2(x-3)^2-2 or first choice.

4 0

3 years ago