Area of a triangle = (1/2)*base*height
For both of the triangles, you have the base (8.8 for the triangle on the left, 7.6 for the triangle on the right) and the side lengths, but not the height. But since both are isosceles triangles, you can find the height using the pythagorean theorem.
5.
First divide the triangle vertically into two triangles (see attached picture). Now you have two right triangles, you can apply the pythagorean theorem on either one of them to find the height. The pythagorean theorem says that for a right triangle,
, where c is the hypotenuse and a and b are the sides of the triangle.
Substituting the given values and rounding to nearest tenth:

Now that you have the height, you can find the area of the entire triangle.
A = (1/2)*base*height
A = (1/2)*8.8*9.0 = 39.6
6.
Same procedure.

A = (1/2)*base*height
A = (1/2)*7.6*9.2 = 35.0
Answer:
The equation in slope-intercept form of the line that crossed the x-axis at 36 and is perpendicular to the line represented by y = -4/9x + 5 is y=9/4x +36
Step-by-step explanation:
Iiiiiiuuuuuuuuuuhgfkfgjkvhv
Answer:
p = 23 and p = -22
Step-by-step explanation:
| 2p -1 | =45
Absolute value equations have 2 solutions, one positive value and one negative
2p-1 = 45 and 2p-1 = -45
Add 1 to all sides
2p-1+1 = 45+1 and 2p-1+1 = -45+1
2p = 46 2p = -44
Divide by 2
2p/2 = 46/2 and 2p/2 = -44/2
p = 23 and p = -22