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8090 [49]
3 years ago
13

The bakers at healthy bakery can make 320 bagels in 5 hours. How many bagels can they bake on 20 hours? What was that rate per h

our
Mathematics
1 answer:
mash [69]3 years ago
3 0

4 times 5 is 20 so 320 times 4 is 1,280

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the three sides of a triangle measure 9.97 meters 10.1 metres and 0.53 metres what is the distance around the triangle
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The answer is 20.6 meters.
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Sarah earns $7.50 per hour babysitting and $5.00 per hour walking dogs. Last week she worked h hours babysitting and twice as ma
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Graph the function f(x) = -42-4+ 5 on the axes below. You must plot the
valentina_108 [34]

Answer:

- attached graph

- Horizontal Asymptote: y = 5

- twon whole number points are (4,4) and (5,1)

Step-by-step explanation:

- Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote

y = -4^(x-4) + 5

  = -4^(4-4) + 5

  = -4^(0) + 5

  = -1 + 5

  = 4

y = -4^(x-4) + 5

  = -4^(5-4) + 5

  = -4^(1) + 5

  = -4 + 5

  = 1

7 0
2 years ago
At a college, 71% of courses have final exams and 43% of courses require research papers. Suppose that 26% of courses have a res
Romashka [77]

Answer:

There is an 88% probability that a course has a final exam or a research paper.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

E is the probability that a course has final exam.

P is the probability that a course requires research paper.

We have that:

E = e + (E \cap P)

In which e is the probability that a course has final exam but does not require research paper and E \cap P is the probability that a course has both of these things.

By the same logic, we have that:

P = p + (E \cap P)

(a) Find the probability that a course has a final exam or a research paper.

This is

Pr = e + p + (E \cap P)

Suppose that 26% of courses have a research paper and a final exam.

This means that

E \cap P = 0.26

43% of courses require research papers.

So P = 0.43

P = p + (E \cap P)

0.43 = p + 0.26

p = 0.17

71% of courses have final exams

So E = 0.71

E = e + (E \cap P)

0.71 = e + 0.26

e = 0.45

The probability is

Pr = e + p + (E \cap P) = 0.45 + 0.17 + 0.26 = 0.88

There is an 88% probability that a course has a final exam or a research paper.

7 0
4 years ago
The table of values below represent an exponential function. Write an exponential equation that models the data. x y -2 22 -1 15
noname [10]

Answer:

What are the answer choices?

Step-by-step explanation:

8 0
3 years ago
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