Solve to find the value of x.

Which proportion below has a vertical

creativ13 [48]

Answer:

1 x 6 = 6 and 3 x 6 = 18

Step-by-step explanation:

3 0

4 years ago

The transformation of 'f' is represented by 'g'. Write a rule for g. f(x)=\root(3)(x). Then show your check steps.

podryga [215]

Answer:

$g(x)=-2\sqrt[3]x$

or

$g(x) = -2f(x)$

Step-by-step explanation:

Given

$f(x) = \sqrt[3]x$

Required

Write a rule for g(x)

See attachment for grid

From the attachment, we have:

$(x_1,y_1) = (-1,2)$

$(x_2,y_2) = (1,-2)$

We can represent g(x) as:

$g(x) = n * f(x)$

So, we have:

$g(x) = n * \sqrt[3]x$

For:

$(x_1,y_1) = (-1,2)$

$2 = n * \sqrt[3]{-1}$

This gives:

$2 = n * -1$

Solve for n

$n = \frac{2}{-1}$

$n = -2$

To confirm this value of n, we make use of:

$(x_2,y_2) = (1,-2)$

So, we have:

$-2 = n * \sqrt[3]1$

This gives:

$-2 = n * 1$

Solve for n

$n = \frac{-2}{1}$

$n = -2$

Hence:

$g(x) = n * \sqrt[3]x$

$g(x)=-2\sqrt[3]x$

or:

$g(x) = -2f(x)$

4 0

3 years ago

Explain how you could use a number line to show that -4+3 and 3+(-4) have the same value.which property of addition states that

Anna007 [38]

For -4+3,
1. start with zero
2. move to left (-x axis) for 4 units (-4)
3. then move to right (+x axis) for 3 units (+3)

For 3+(-4)
1. Start with zero
2. Move the point to right side by 3 units (+3)
3. then move the point to the left by 4 units (-4)

For both you'll stop at -1.

8 0

3 years ago

Which of the following are solutions to the equation below?

Natasha2012 [34]

Both A and C would be solutions to the equation.

In order to solve for this you must first get the equation equal to 0.

2x^2+5x+8=6 ----> subtract 6 from both sides
2x^2 + 5x + 2 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.

a = 2 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 2 (because it is the end number)

Now we can plug these values into the quadratic equation.

$\frac{-b +/- \sqrt{b^{2} - 4ac } }{2a}$

$\frac{-5 +/- \sqrt{5^{2} - 4(2)(2) } }{2(2)}$

$\frac{-5 +/- \sqrt{9} }{4}$

$\frac{-5 +/- 3 }{4}$

$\frac{-5 + 3 }{4}$ or -1/2 for the first answer

$\frac{-5 - 3 }{4}$ or -2 for the second answer

5 0

3 years ago

Please help i rlly need itttt

Olenka [21]

Answer:

The value of x is the value where the line crosses the x-axis!

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Hope this helps!!

Please tell me if I have made a mistake!!

I enjoy learning from them:)

8 0

2 years ago

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