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OLEGan [10]
3 years ago
11

In the right hexagonal pyramid below. The hexagonal base is regular and has sides that are 8 units long. The altitude of the pyr

amid is 18 units. Determine the volume of the pyramid to the nearest cubic unit.
Mathematics
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

The volume is <em>997.62 cubic units.</em>.

Step-by-step explanation:

We are given the following details:

The pyramid has a regular hexagonal base i.e. each side of hexagon is equal.

Side of hexagonal base, a = 8 units

Altitude of pyramid, h = 18 units

We have to find the volume of pyramid.

Formula:

V = \dfrac{1}{3} \times B \times h

Where, B is the area of base of pyramid.

h is the height/altitude of pyramid

To calculate B:

Here, base is a hexagon with side 8 units.

\text{Area of hexagon, B }= 6 \times \dfrac{\sqrt{3}}{4}a^{2}

Here, a = 8 units

\Rightarrow B = 6 \times \dfrac{\sqrt{3}}{4}\times 8^{2}\\\Rightarrow B = 166.27\text{ square units}

Putting values of B and h in Formula of volume:

\Rightarrow V = \dfrac{1}{3} \times 166.27 \times 18\\\Rightarrow V = \dfrac{2992.89}{3} = 997.62\text{ cubic units}

Hence, the volume is <em>997.62 cubic units.</em>

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PLEASE HELP
den301095 [7]

Answer:

Option A

Step-by-step explanation:

multiple each coordinate by 1/2

8 0
3 years ago
Help peeps i shall give brainalist .-_-.
Oksana_A [137]
The answer is B
R=89.49/2 pi
It give you the circumference and you need to find the radius
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What is the volume of the solid generated when the region in the first quadrant bounded by the graph of y=x^3, the x-axis, and t
son4ous [18]

Answer:

The first thing we need to do is to find the area bounded by:

y = x^3

y = 0

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This means that the area of the bounded region is 4 square units.

Now, if we do a full rotation around the x-axis, the volume generated will be equal to the area that we obtained times 2*pi units.

The volume is:

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