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kompoz [17]
3 years ago
6

Find the area of a rectangle that is 8 ft long and 4 ft wide.

Mathematics
2 answers:
Ad libitum [116K]3 years ago
5 0

Answer: 32ft squared

Step-by-step explanation: since area of a rectangle is length x breadth.

It then becomes 8ft x 4ft = 32ft²

vazorg [7]3 years ago
5 0

Answer:

32ft squared...

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A triangular pyramid has lateral faces with bases of 6 meters and height of 9 meters. The area of the base of the pyramid 15.6 m
jasenka [17]
To find surface area, you can find the area od all sides and add them together
First, area of an triangle is 1/2 length times width
So you do 1/2 6*9= 1/2 54=  27  The area of the three triangles are 27
27 times 3 is  81
81 plus the base of 15.6 is 96.6
The surface area is 96.6 meters squared

7 0
3 years ago
Can someone help me with this question please?
ra1l [238]
The answer is 3 and you have to subsitute -6 in for n to get your answer
4 0
3 years ago
Solve<br> x2 - 8x + 14 = 2x - 7
BabaBlast [244]

Answer:

x=7, x=3

Step-by-step explanation:

             x^{2} -8x+14=2x-7

x^{2} -8x-2x+14+7=0

            x^{2} -10x+21=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x= \frac{-b\pm \sqrt{b^2-4ac}}{2a}

positive

x=\frac{-\left(-10\right)+\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=7

negative

x=\frac{-\left(-10\right)-\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=3

7 0
3 years ago
Please solve and graph each inequality x-7&lt;-12
Keith_Richards [23]

For this case we must resolve the following inequality:

x-7

Adding 7 to both sides of the inequality:

x

Different signs are subtracted and the major sign is placed.

x

Thus, the solution is given by all the values of "x" less than -5.

The solution set is: (-∞, - 5)

Answer:

x

See attached image

3 0
3 years ago
Write an equivalent fraction for the whole number 6?
Keith_Richards [23]
6*2 = 12
12/2 = 6

So, the answer could be 12/2
6 0
3 years ago
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