This rectangular prism was constructed by placing unit cubes together without any gaps or overlaps.
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Check the picture below.
so, the diameter of the sphere, is the same as a side's length of the cube, bearing in mind that all sides in a cube are the same length.
since all sides in the cube are "d", then its volume is V = d*d*d or V = d³.
![\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\ -----\\ V=972\pi \end{cases}\implies 972\pi =\cfrac{4\pi r^3}{3}\implies 2916\pi =4\pi r^3 \\\\\\ \cfrac{2916\pi }{4\pi }=r^3\implies 729=r^3\implies \sqrt[3]{729}=r\implies \boxed{9=r}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20sphere%7D%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0A-----%5C%5C%0AV%3D972%5Cpi%20%0A%5Cend%7Bcases%7D%5Cimplies%20972%5Cpi%20%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D%5Cimplies%202916%5Cpi%20%3D4%5Cpi%20r%5E3%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B2916%5Cpi%20%7D%7B4%5Cpi%20%7D%3Dr%5E3%5Cimplies%20729%3Dr%5E3%5Cimplies%20%5Csqrt%5B3%5D%7B729%7D%3Dr%5Cimplies%20%5Cboxed%7B9%3Dr%7D)
since the diameter is twice as much as the radius, thus d = 2r, or namely d = 18.
therefore, the volume of the cube will be V = 18³.
so, the diameter of the sphere, is the same as a side's length of the cube, bearing in mind that all sides in a cube are the same length.
since all sides in the cube are "d", then its volume is V = d*d*d or V = d³.
since the diameter is twice as much as the radius, thus d = 2r, or namely d = 18.
therefore, the volume of the cube will be V = 18³.