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3 years ago

Dave can drive 160 miles on a tank of gas. Approximately how many tanks of gas will he need to drive 880 miles?

2 answers:

8 0

How many times does he have to drive 160 miles in order to cover 880 ?

880/160 = 5.5 times

He'll need 5 complete tanks of gas, and 1/2 of another one.

stellarik [79]3 years ago

4 0

$160\ miles\ \rightarrow\ \ 1\ tank\ of\ gas\\880\ miles\ \rightarrow\ x\\\\160\cdot x=880\ /:160\\\\x= \frac{880}{160} \ \ \ \Rightarrow\ \ x= \frac{11}{2} \ \ \ \Rightarrow\ \ x= 5.5\\\\Ans.\ 5.5\ tank\ of\ gas$

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Darnel's retirement party cost $33, plus an additional $1 for each guest he invites. What is the maximum number of guests there

Karolina [17]

Answer: the maximum number of guests that he can invite would be 9

Step-by-step explanation:

Darnel's retirement party cost $33, plus an additional $1 for each guest he invites. Assuming Darnel wants to invite x guests to his retirement party, the total amount of money that Darnel would spend is

33 + x

if darnel can afford to spend a total of $42 on his retirement party, then

42 = 33 + x

x = 42 - 33 = 9

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3 years ago

Find the solutions for a triangle with a = 16, c =12, and B = 63º.

maks197457 [2]

Answer:

b. A = 71.6°; C = 45.40°; b =15.0

Step-by-step explanation:

The missing values can be found with the help of the Law of Cosine and properties of triangles:

Side b (Law of Cosine)

$b = \sqrt{a^{2}+c^{2}-2\cdot a \cdot c \cdot \cos B}$

$b = \sqrt{16^{2}+12^{2}-2\cdot (16)\cdot (12) \cdot \cos 63^{\circ}}$

$b \approx 15.022$

Angle A (Law of Cosine)

$\cos A = -\frac{a^{2} - b^{2}-c^{2}}{2\cdot b \cdot c}$

$\cos A = - \frac{16^{2}-15.022^{2}-12^{2}}{2\cdot (15.022)\cdot (12)}$

$\cos A = 0.315$

$A= \cos^{-1} 0.315$

$A \approx 71.639^{\circ}$

Angle C (Sum of internal angles in triangles)

$C = 180^{\circ} - 63^{\circ} - 71.639^{\circ}$

$C = 45.361^{\circ}$

Hence, the right answer is B.

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3 years ago

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I got the height to be 4

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Step-by-step explanation:

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