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Sunny_sXe [5.5K]
4 years ago
8

What are the prime factors of 625

Mathematics
1 answer:
kobusy [5.1K]4 years ago
6 0
Let's see what we can get by dividing 625 by 5, as it ends with a 5:
625/5 = 125
So we have 5 as one of our factors. Let's divide again by 5:
125/5 = 25
Our current prime factors now are 5 and 5, but we aren't finished. Divide again by 5:
25/5 = 5
Now we know that the prime factorization of 625 is 5 * 5 * 5 * 5, which can also be shown as 5⁴.
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ahrayia [7]
9(2j+7+5j) Foil this out to get 18j+7+45j then 63j+7

Answer: 18j+7+45j , 63j+7 I think
8 0
3 years ago
Read 2 more answers
Two-thirds of the sum of a number squared and 5 is fourteen
RideAnS [48]

Answer:

2/3( x^2 + 5 ) = 14 or 2/3x^2 - 32/3

Step-by-step explanation:

Part 1:

Two-thirds ( 2/3 )

of the ( (---) )

sum ( + )

of a number squared ( x^2 ) and 5 ( + 5 )

is fourteen ( = 14 )

Part 2 (Not super confident about):

2/3( x^2 + 5 ) = 14

2/3x^2 + 10/3 = 14

2/3x^2 - 32/3

Hopefully this helps!

Brainliest please?

7 0
3 years ago
enrollment in the ski/snowboard club increased by 30% this year. there are now 182 students in the club. how many students were
eduard
Enrolement increased by 30% that means last year=100%
incease of 30%=30+100=130% now

now=182

percent means parts out of 100 so
130%=130/100=13/10


182=13/10 of x (x represents the number last year)
of means multipy so
182=13/10 times x
multiply both sides by 10/13 to clear fraction
182 times 10/13=x=140



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8 0
3 years ago
The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by
Vikentia [17]

The answer will be t = sin((m.\frac{\pi}{6})+55) average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\

suppose x = m.\frac{\pi}{6}+55 and \frac{\pi}{2} = 90 degree

We know, cos(x+90°) = - sin(X)

⇒ cos((m.\frac{\pi}{6})+55+90degree)degree = -sin((m.\frac{\pi}{6})+55)

⇒ t = sin((m.\frac{\pi}{6})+55)

Hence the answer will be t = sin((m.\frac{\pi}{6})+55) average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

To learn more visit:

brainly.com/question/27441712

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2 years ago
How many inches are there a in 13 feet
Andrews [41]

Answer:

156

Step-by-step explanation:

13 x 12 = 156

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3 years ago
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