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patriot [66]
3 years ago
5

1. Which other expression has the same value as (-14) - 8?​

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
6 0

Answer: −22

Step-by-step explanation:

=−14−8

=−14+−8

=−22

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What is 25% of 40? Show Work please
goldenfox [79]

25% = 1/4

1/4(40)

Divide 40 by 4 to remove the 1/4

10

25% of 40 is 10.

7 0
4 years ago
Read 2 more answers
Differentiate 5^x in respect to x
geniusboy [140]

Given:

The term is 5^x.

To find:

The differentiation of 5^x with respect to x.

Solution:

Formula used:

\dfrac{d}{dx}a^x=a^x\log(a)

Let the given function is:

f(x)=5^x

Here, a=5.

Differentiate the given function with respect to x.

f'(x)=5^x\log(5)

Therefore, the derivative of 5^x with respect to x is 5^x\log(5).

3 0
3 years ago
Which of the following numbers can be expressed using negative exponents? Select one: a. .0005216 b. 5,216 c. -5,216 d. 52.16
Andreas93 [3]

Answer:

black people

Step-by-step explanation:

4 0
3 years ago
What is the square root of 25p^3 expressed in simplified form?
notka56 [123]
The first step to solving this is to factor out the perfect square of 5²
\sqrt{ 5^{2}  p^{3} }
next,, factor out the perfect square of p³
\sqrt{ 5^{2}  p^{2} x p}
the root of a product is equal to the product of the roots of each factor 
√5² √p² √p
now reduce the first index of the radical and the exponent with 2
5√p² √p
then reduce the second index of the radical and exponent with
5p√p
this means that the correct answer to your question is 5p√p
let me know if you have any further questions
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6 0
4 years ago
En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand
Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Donde:

F_{1} - Fuerza experimentada por el elefante, medida en newtons.

F_{2} - Fuerza aplicada sobre el plato pequeño, medida en newtons.

A_{1} - Área del plato grande, medida en metros cuadrados.

A_{2} - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g (2)

Donde:

D_{1} - Diámetro del plato grande, medido en centímetros.

D_{2} - Diámetro del plato pequeño, medido en centímetros.

m - Masa del elefante, medida en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que D_{1} = 0.75\,m, D_{2} = 0.13\,m, m = 2900\,kg y g = 9.807\,\frac{m}{s^{2}}, entonces la fuerza a aplicar al émbolo pequeño es:

F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{2} = 854.473\,N

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0
3 years ago
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