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3 years ago

What is the interquartile range of the data? 53, 62, 67, 71, 83, 94, 102, 105

Mathematics

1 answer:

Vsevolod [243]3 years ago

6 0

The IQR is 38 bc the Q1 is 62 and Q3 is 100. 100-62=38

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9/10 - 3/14_______ps in simplest form

neonofarm [45]

9/19 - 3/14
= 126/140 - 57/140
= 69/140

3 0

3 years ago

The surface area of 3ft, 7ft, 2ft

Xelga [282]

Answer: 82 ft squared

Step-by-step explanation: The surface area is 2( wl + hl + hw)

so the width is 2 the length is 7 and the height is 3

so it's 2( 14 + 21 + 6) = 2(41) = 82

6 0

3 years ago

A tennis ball has a radius of about 1.4 inches What is the volume of the tennis ball to the nearest half inch.? Use 3.14 as an a

Ilya [14]

Answer:

Volume of tennis ball = 11.49 inch³

Step-by-step explanation:

Given:

Radius of tennis ball = 1.4 inches

Value of π = 3.14

Find:

Volume of tennis ball

Computation:

Volume of sphere = [4/3][π][r]³

Volume of tennis ball = [4/3][π][Radius of tennis ball]³

Volume of tennis ball = [4/3][3.14][1.4]³

Volume of tennis ball = [1.333][3.14][1.4]³

Volume of tennis ball = [1.333][3.14][2.744]

Volume of tennis ball = [4.1856][2.744]

Volume of tennis ball = 11.4852

Volume of tennis ball = 11.49 inch³

6 0

3 years ago

Find dy du , du dx , and dy dx .

dangina [55]

Answer:

a) $\frac{dy}{du}=5(x^2 +1)^4$ , $\frac{du}{dx}=2x$ , $\frac{dy}{dx}=10x(x^2+1)^4$

b) $\frac{dy}{du}=4(4x^2-x+6)^3$ , $\frac{du}{dx}=8x-1$ , $\frac{dy}{dx}=4(8x-1)(4x^2-2+6)^3$

Step-by-step explanation:

We can use the chain rule in the following form: is u=u(x) is a differentiable function depending on x and y=y(u) is a differentiable function depending on u, then $\frac{dy}{dx}=\frac{dy}{du} \frac{du}{dx}$ .

a) $\frac{dy}{du}=\frac{d}{du} (u^5)=5u^4=5(x^2 +1)^4$ from the power rule.

$\frac{du}{dx}=\frac{d}{dx} (x^2 +1)=2x$ .

From the previous parts and the chain rule, $\frac{dy}{dx}=\frac{dy}{du} \frac{du}{dx}=5(x^2 +1)^4(2x)=10x(x^2+1)^4$

b) $\frac{dy}{du}=\frac{d}{du} (u^4)=4u^3=4(4x^2-x+6)^3$

$\frac{du}{dx}=\frac{d}{dx} (4x^2-x+6)=8x-1$ from the power and sum rules.

Then, $\frac{dy}{dx}=\frac{dy}{du} \frac{du}{dx}=4(4x^2 -x+6)^3(8x-1)=4(8x-1)(4x^2-x+6)^3$

8 0

3 years ago

Please help asap

djverab [1.8K]

Answer:

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5 0

2 years ago

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