Answer:
<h2>90 min or 1hr 30 mins</h2>
Step-by-step explanation:
Even though the options to choose from are not given in this question we can try and lay our hand on the most likely equation for the number of minutes Jack reads his book.
firstly on a daily Jack reads a total of = 8+10 = 18 mins
He attends school from Mon- fri = 5 days
Now on a weekly basis jack reads = 5*18
in other words, the equation is simply the number of days times the time spent to read his book per day
hence this is = 90 min or 1hr 30 mins
It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.
Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is
<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)
The cosine of the angle between the vectors can be obtained from the dot product identity,
<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>) ==> cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)
so that
<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)
For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is
<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))
==> <em>W</em> ≈ 5.12 J
(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).
Answer:
The answer of the question is 5
Answer: 27.958333333333333333333333333333........
Step-by-step explanation: Use long division method or do rounding method round each number and divide.
Answer:
see the explanation
Step-by-step explanation:
we know that
The area of the base of a cylinder is given by the formula
where
r is the radius of the circular base
If the radius is doubled
then
The new base area is
so
therefore
The new area of the base is 4 times the area of the original base
