Answer:
Step-by-step explanation:
a circle will satisfy the conditions of Green's Theorem since it is closed and simple.
Let's identify P and Q from the integral
, and
Now, using Green's theorem on the line integral gives,

Answer:
circle= 5, triangle= 3
Step-by-step explanation:
Please see attached picture for full solution.
Move constant to the right-hand side and change its sign
2x^2 + 8 = -2 + 7
-2 + 7 = 5
Divide both sides of the equation by
x^2 + 4x = 5/2
Add (4/2^2) to both sides of the equation
x^2 + 4x + (4/2)^2 = 5/2 + (4/2)^2
factor the expression
(x + 4/2)^2 = 13/2
reduce the fraction by 2
(x + 2)^2 = 13/2
now solve equation for x
Answer:a
Step-by-step explanation:
u pick the right one
Answer:

Step-by-step explanation:
Start with:

Distribute the
into
:

Combine like terms:

Add
to both sides of the equation:

Subtract
from both sides of the equation:

Divide both sides of the equation by the coefficient of
, which is
:

or
