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algol13
3 years ago
9

Stuck, please help and give explanation thank you.

Mathematics
1 answer:
KatRina [158]3 years ago
3 0
The price of Deluxe=D
the price of standard- S

D=S+5
2D+3S=47,5
2*(S+5)+3S=47,5
2S+2*5+3S=47,5
5S+10=47,5
5S=47,5-10
5S=37,5
S=37,5:5
S=7,5 $ the price of standard Chocolates

D=7,5+5=12,5$
D=12,5$

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SVETLANKA909090 [29]
7+k=?
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9+s=?
x-4=?
x-9=?
8+f=?
d/4=? or d÷4=?
4 0
3 years ago
if syn spends 15 minutes running, he burns 200 calories. how long would it take Syn to burn 150 calories?
kramer

Answer:

<h2>11.25min</h2>

Step-by-step explanation:

In this problem, we first need to find the rate at which syn burns calories per minute

so in 15mins, he burns 200 calories

    in 1 mins he will burn x

x= 200/15

x=13.33 calories per min this is the rate

So in one minute he will burn 13.33 calories

Now using the idea of rate=quantity/time

the rate=13.33

quantity=15 calories

time=?

time=quantity/rate

time=150/13.33

time=11.25min

   Alternatively

(very fast approach)

         if syn spend 15min to burn 200 cal

then he will spend x min to burn 150 cal

cross multiply

x=(150*15)/200

x=2250/200

x=11.25mins

5 0
3 years ago
Mc Kennie had two black licorice each 25cm long. He gave Pierre 1⁄5 cm of a licorice stick. How much did he have remaining?
kondaur [170]

Answer:  He had one whole 25cm stick, and 1 10cm long stick of licorice.

Step-by-step explanation:

25-15=10

He had a total of 35 cm of licorice.

3 0
3 years ago
Solve for x<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4x%20-%206%7D%7B4%7D%20%20%3D%20%20%5Cfrac%7B2x%20%2B%205%7D%7B3%7
Marizza181 [45]

Answer:

x = 9.5

Step-by-step explanation:

Given

\frac{4x-6}{4} = \frac{2x+5}{3} ( cross- multiply )

3(4x - 6) = 4(2x + 5) ← distribute parenthesis on both sides

12x - 18 = 8x + 20 ( subtract 8x from both sides )

4x - 18 = 20 ( add 18 to both sides )

4x = 38 ( divide both sides by 4 )

x = \frac{38}{4} = 9.5

6 0
4 years ago
What is the quotient of 7^2/2x+6 divided by 3x-5/x+3
Reil [10]

\bf \cfrac{7^2}{2x+6}\div \cfrac{3x-5}{x+3}\implies \cfrac{7^2}{2x+6}\cdot \cfrac{x+3}{3x-5}\implies \cfrac{49}{2~~\begin{matrix} (x+3) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\cdot \cfrac{\begin{matrix} x+3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }{3x-5}\implies \cfrac{49}{2(3x-5)}

6 0
4 years ago
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