Hello!
Kinematics by definition is the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.
Answer:
what question ?
Step-by-step explanation:
i did not get it what question?
40 I am pretty sure that is the right answer
Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that
<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>
<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>
where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.
Then the sum is
<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>
and its magnitude is
||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)
… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))
… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))
… = √(16 + 16 cos(135° - 45°) + 4)
… = √(20 + 16 cos(90°))
… = √20 = 2√5
Answer:
8xy-3y + 2(9x-5y+4) = 18
Step-by-step explanation:
We need to find the value of the given expression:
8xy-3y + 2(9x-5y+4) ....(1)
when x = 3 and y = -4
Put the values of a and y in equation (1)
8×3×(-4)-3(-4)+ 2(9×3-5(-4)+4)
= -96 +12 + 2(27 + 20 +4)
= -84 + 2(51)
= -84 + 102
= 18
Hence, the value of the given expression is 18.
