Answer:
Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
The 3 angles of a triangle add up to 180 degrees. If all 3 sides are different in length then the angles are also different.
Its choice 1
The unit normal for the given plane is <5,2,-1>.
The equation of the plane parallel to the given plane passing through (5,5,4) is therefore
5(x-5)+2(y-5)-1(z-4)=0
simplify =>
5x+2y-z=25+10-4=31
Answer: the plane through (5,5,4) parallel to 5x+2y-z=-6 is 5x+2y-z=31
A right triangle can only be formed when you use the 3/4/5 rule.
The 3/4/5 rule is a^2 + b^2 = c^2.
We will use 10 for a, 15 for b, and 20 for c.
a^2 + b^2 = c^2
Plug in 10 for a, 15 for b, and 20 for c.
10^2 + 15^2 = 20^2
10^2 = 100
15^2 = 225
20^2 = 400
100 + 225 = 400
This is not applicable, as 100 + 225 = 325.
Your answer is:
No, 10,15,20 does not form a right triangle.
I hope this helps!
Answer: 3
Step-by-step explanation: i don't know how it explain it
