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Galina-37 [17]
3 years ago
15

What is 2.25% of 24 please help

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
4 0
0.54

24 x 0.0225 would get u 0.54
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Hi hottie, pls help me !
yulyashka [42]

Answer:

1200

0.65

The answers are in the function

6 0
3 years ago
Four students are trying to find the rule that translates point N(–2, –4) to N prime (2, 4). Each student’s reasoning is shown b
liraira [26]

Answer:

Lo's answer is correct and it is a translation because applying the rule (x+4, y+8) on the coordinates N(-2, -4) will gives us N'(2,4).

Step-by-step explanation:

i) though Raheem is mathematically correct the question asks for a translation which means that we can only use addition and/or subtraction and not multiplication. So Raheem's answer is therefore incorrect.

ii) Casey's answer is incorrect as applying the rule (x+2, y+4) on the coordinates N(-2, -4) will gives us (0,0) and not N'(2,4)

iii) Andrew's answer is also incorrect as applying the rule (x+4, y+0) on the coordinates N(-2, -4) will gives us (2,-4) and not N'(2,4).

iv) Lo's answer is correct and it is a translation because applying the rule (x+4, y+8) on the coordinates N(-2, -4) will gives us N'(2,4).

6 0
3 years ago
Read 2 more answers
Please help me!!!!!!!!
Marina CMI [18]
I honestly don't know because i'm only in sixth grade but I think that it might be 30*.
5 0
3 years ago
Suppose X has an exponential distribution with mean equal to 23. Determine the following:
e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean equal to 23.

This means that m = 23, \mu = \frac{1}{23} = 0.0435

(a) P(X >10)

P(X > 10) = e^{-0.0435*10} = 0.6473

So

P(X > 10) = 0.6473

(b) P(X >20)

P(X > 20) = e^{-0.0435*20} = 0.4190

So

P(X > 20) = 0.4190

(c) P(X <30)

P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

P(X > x) = e^{-\mu x}

0.05 = e^{-0.0435x}

\ln{e^{-0.0435x}} = \ln{0.05}

-0.0435x = \ln{0.05}

x = -\frac{\ln{0.05}}{0.0435}

x = 68.87

5 0
3 years ago
Find the range of the function for the given domain, f(x)=3x+3; (-2,-1,0,1,2)
stich3 [128]

Answer:

Range: (-3,0,3,6,9)

Step-by-step explanation:

We need to evaluate each value in the domain of the function, so

f(-2)=3(-2)+3=-6+3=-3

f(-1)=3(-1)+3=-3+3=0

f(0)=3(0)+3=0+3=3

f(1)=3(1)+3=3+3=6

f(2)=3(2)+3=6+3=9

8 0
3 years ago
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