AVERAGE between 90 and 100%
means not including 90 and 100% but not including 90 or 100%
average=(sum of values in set)/(how many values in the set)
so
4 exams, so there are 4 values
average=(sum)/4
the sum is the known+unknwon
sum=76+99+86+x
so
90<span><</span>average and average <span><</span>100
or
90<span><</span>average<span><</span>100
lets say average=a
a=sum/number
a=(76+99+86+x)/4
90<(76+99+86+x)/4<100
90<(76+99+86+x)/4 and (76+99+86+x)/4<100
solve each for x and find intersection
90<span><</span>(76+99+86+x)/4
times 4 both sides
360<span><</span>261+x
minus 261 both sides
99<span><</span>x
(76+99+86+x)/4<u><</u>100
times 4 both sides
261+x<u><</u>400
minus 261 both sides
x<u><</u>139
so
99<u><</u>x<u><</u>139
since max score is 100
99<u><</u>x<u><</u>100
interval notaion is
[99,100]
answer is 2nd one
For ∆RNM ~ ∆RPQ
=> RN/RP = RM/RQ
=> 7/8 = 10/14 which is wrong
So ∆RMN is not similar to ∆RQP
Answer:
D. 6x^3 + 8x
Step-by-step explanation:
2x(3x^2 + 4)
Distribute the 2x
2x(3x^2) +2x( 4)
6x^3 +8x
Answer:
A
Step-by-step explanation:
if these are fractions than its A.
2x-4=2
4x-5=5/4