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melisa1 [442]
2 years ago
5

I just need help on the question circled below. (I need the answer ASAP.)

Mathematics
1 answer:
77julia77 [94]2 years ago
6 0
2.5+ 2.5= 5 miles i think
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Graph the linear function using slope intercept form<br> y=2x+6
Stella [2.4K]
Start in the middle and go up 6 then draw a dot, after that you go up two and right one and do it all the way you can and then to go the opposite way go down two and left one. Hope this helps
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Find the area to the nearest hundredth
Savatey [412]

Answer:

9.0586 OR

9.06

Step-by-step explanation:

IDK, used fusion 360

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2 years ago
h(t)=(t+3) 2 +5 h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plu
lesya692 [45]

Answer:

1

Step-by-step explanation:

If I understand the question right, G(t) = -((t-1)^2) + 5 and we want to solve for the average rate of change over the interval −4 ≤ t ≤ 5.

A function for the rate of change of G(t) is given by G'(t).

G'(t) = d/dt(-((t-1)^2) + 5). We solve this by using the chain rule.

d/dt(-((t-1)^2) + 5) = d/dt(-((t-1)^2)) + d/dt(5) = -2(t-1)*d/dt(t-`1) + 0 = (-2t + 2)*1 = -2t + 2

G'(t) = -2t + 2

This is a linear equation, and the average value of a linear equation f(x) over a range can be found by (f(min) + f(max))/2.

So the average value of G'(t) over −4 ≤ t ≤ 5 is given by ((-2(-4) + 2) + (-2(5) + 2))/2 = ((8 + 2) + (-10 + 2))/2 = (10 - 8)/2 = 2/2 = 1

Click to let others know, how helpful is it

3 0
3 years ago
Ana has been adding $30 to her saving account every month. Which model could represent the money in Ana’s saving account (y) aft
Gekata [30.6K]

Answer:

y = 30x

Step-by-step explanation:

y is the amount of money

30 is the constant, the amount of money she gets per x, month

5 0
3 years ago
Silas had 3 times as much money as Raja. Silas spent $84 of his money to buy a birthday gift for his grandma while Raja was awar
Tamiku [17]

Answer:

Total amount Silas and Raja has at first = $252

Step-by-step explanation:

Let,

Amount Silas had = x

Amount Raja had = y

According to given statement;

x = 3y       Eqn 1

x-84 = y+42     Eqn 2

Putting value of x from Eqn 1 in Eqn 2

3y - 84 = y+42

3y-y = 42+84

2y = 126

Dividing both sides by 2

\frac{2y}{2}=\frac{126}{2}\\y=63

Putting y = 63 in Eqn 1

x = 63(3)

x = 189

Total amount they had = 189 + 63 = $252

Hence,

Total amount Silas and Raja has at first = $252

8 0
2 years ago
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