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3 years ago

Brenda is finding the product of –3r and. Is she correct? If not, what changes should be made?

Mathematics

1 answer:

vlabodo [156]3 years ago

7 0

Answer:

Step-by-step explanation

To remove the brackets, she should do this in two steps.

- 3r( - 2r^2) = 6r^3

- 3r(3r) = - 9r^2

Combine

6r^3 - 9r^2

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Assume the monthly interest rate is 1/12 of the annual interest rate . you maintain an average balance of $450 on your credit ca

masya89 [10]

Answer:

The monthly interest payment would be $ 9

Step-by-step explanation:

Given,

The average balance of the credit card = $ 450,

Annual rate of interest = 24%,

∵ Monthly interest rate is 1/12 of the annual interest rate,

Thus, the monthly interest rate = $\frac{1}{12}\text{ of }24\%$

$=2\%$

Hence, the monthly interest payment = 2% of credit card balance

= 2% of 450

$=\frac{2\times 450}{100}$

$=\frac{90}{10}$

= $ 9

3 0

3 years ago

Simplify, state all restrictions.

Kipish [7]

The simplified expression is $\frac{1 - x - y}{x + y}$ and the restriction is $y \ne -x$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\frac{x - y}{4x^2 - 8xy + 3y^2} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{x^2 - y^2} -1$

Express x^2 - y^2 as (x + y)(x - y) and factorize other expressions

$\frac{x - y}{(2x - y)(2x - 3y)} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1$

Rewrite the expression as products

$\frac{x - y}{(2x - y)(2x - 3y)} \times \frac{2x - 3y}{2x + y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1$

Cancel out the common factors

$\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{4x^2 - y^2}{(x + y)} -1$

Express 4x^2 - y^2 as (2x - y)(2x + y)

$\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{(2x - y)(2x + y)}{(x + y)} -1$

Cancel out the common factors

$\frac{1}{x + y} -1$

Take the LCM

$\frac{1 - x - y}{x + y}$

Hence, the simplified expression is $\frac{1 - x - y}{x + y}$ and the restriction is $y \ne -x$

Read more about expressions at:

brainly.com/question/723406

#SPJ1

7 0

1 year ago

This is from Khan academy I have to attach a PNG if you can help me solve it! Thank you!

Elenna [48]

Step-by-step explanation:

$\frac{5 {}^{ - 4x + 7} }{125 {}^{x} }$

$\frac{5 {}^{ - 4x + 7} }{5 {}^{3x} }$

$5 {}^{ - 4x + 7 - 3x}$

$5 {}^{ - 7x + 7}$

7 0

1 year ago

Help help please please

gtnhenbr [62]

✽ Hello there! ✽

4x+9<21

Move all the constants (numbers) to the right, using the opposite operation:

4x<21-9

4x<12

Divide both sides by 4 to isolate x:

x<3

<h2>Therefore, x<3 ✔︎</h2>

Hope this helps!

~Just a felicitous girlie

#HaveASplendidDay

$SilentNature$

8 0

2 years ago

Factor completely.

Marta_Voda [28]

<span>x^2 - 3x - 28 = </span><span>(x - 7)(x + 4)

answer
first one
</span><span>(x - 7)(x + 4)
</span>
hope it helps

8 0

3 years ago