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DiKsa [7]
4 years ago
15

Find class boundaries, midpoint, and width for the class. 57-61

Mathematics
1 answer:
Bond [772]4 years ago
4 0

Answer:

The answer would be -4

You might be interested in
How many times does 20 go into 110
Sindrei [870]

Answer:

20 goes into 110 five-and-a-half times

Step-by-step explanation:

Let's show our work:

20  +  20  +  20   +  20  +    20   +  10      

  \____\_____\____/_____/_____/

                           100

100

= 20 + 20 + 20 + 20 + 20 + 10

Half of 20 = 10

The keyword is half - so that leaves a 0.5 in your answer to "How many times does 20 go into 110."

How many 20's are there? Let's count!

20 + 20 + 20 + 20 + 20

 1      2       3      4       5

So five 20's + one 0.5 = ?

That equals 5.5, because 5 + 0.5 = 5.5

Your answer is 5.5!

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
6 0
3 years ago
Help pls quick!PLS AND TY
JulsSmile [24]

Answer: 12 Fruit Snacks

Hope this Helps!

6 0
3 years ago
Does 10p/2q = 5p/q<br> I think it is not equal but it doesn't seem right.
motikmotik

Answer:

Yes, those two are equal.

Step-by-step explanation

(10p/2q)*2/2=5p/q

5 0
3 years ago
Phoebe bought 2/3 of a yard of green ribbon and 1/3 of a yard white ribbon to use on her quilt. She decided to exchange 1/3 yard
Viefleur [7K]
She has no more white ribbon because she exchanged it for yellow.
4 0
4 years ago
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
4 years ago
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