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4 years ago

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A frame maker is hired by an art museum to make a special frame for a large rectangle painting. The painting is 3 times as long

as it is tall.The expression 2(x+3x) represents the perimeter of the painting, where x represents the length of the short side of the painting in feet. What is the total feet of framing needed if the short side of the painting measures 2.6 feet?

1 answer:

qaws [65]4 years ago

4 0

We have been given that the painting is 3 times as long as it is tall.The expression $2(x+3x)$ represents the perimeter of the painting, where x represents the length of the short side of the painting in feet.

To find the the amount of framing needed when short side of the painting measures 2.6 feet, we will substitute $x=2.6$ in our given expression.

We can simplify our expression as:

$2(x+3x)=2(4x)$

$2(4x)=2(4\times 2.6)$

$2(4x)=2(10.4)$

$2(4x)=20.8$

Therefore, a total of 20.8 feet of framing is needed.

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3 years ago

A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu

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Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

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Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 110, p = 0.2$

So

$\mu = E(X) = np = 110*0.2 = 22$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952$

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 22}{4.1952}$

$Z = 0.715$

$Z = 0.715$ has a pvalue of 0.7626.

X = 17

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{17 - 22}{4.1952}$

$Z = -1.19$

$Z = -1.19$ has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

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4 years ago