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vodka [1.7K]
3 years ago
11

What is the distance between -182 and 265

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0
The distance between -182 and 265 is 83 because if you subtract 265 from-182 it will be 83. the answer is 83.
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population mean =72 and standard deviation =10, what is standard error of distribution of sample means for n=4 and n=25
mixer [17]

Answer:

<u>The standard error of distribution for n = 4 is 5 and for n = 25 is 2.</u>

Step-by-step explanation:

1. Let's review the information given to us for solving the question:

Population mean = 72

Standard deviation  =  10

Sample₁ = 4

Sample₂ = 25

2. For finding the standard error of the mean, we use the following formula:

Standard error = Standard deviation / √Size of the sample

Standard error for Sample₁ = 10/√4

<u>Standard error for Sample₁ = 10/2 = 5</u>

Now, let's find the standard error for Sample₂

Standard error for Sample₂ = 10/√25

<u>Standard error for Sample₂ = 10/5 = 2</u>

4 0
3 years ago
Select ALL the correct answers.
jolli1 [7]

Answer:

(4x+5)(-3x-1) = -12x²-19x-5

Option A:

   (-16x² + 10x - 3) + (4x² - 29x - 2) = -12x²-19x-5

   Option A is correct.

Option B:

   3(x - 5) - 2(6x² + 9x + 5) = -12x²-15x-25

   Option B is wrong.

Option C:

   2(x - 1) - 3(4x² + 7x + 1) = -12x²-19x-5

   Option C is correct.

Option D:

   (2x² - 11x - 9) - (14x² + 8x - 4) = -12x²-19x-5

   Option D is correct.

4 0
2 years ago
HELP PLZZ will give brainliest &lt;3
melisa1 [442]

Answer:

0

1

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

\dfrac{a}{\sin A} = \dfrac{b}{\sin B}

\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}

\dfrac{1}{0.5} = \dfrac{4}{\sin B}

\sin B = 2

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

\dfrac{b}{\sin B} = \dfrac{c}{\sin C}

\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}

\sin C = \dfrac{8.9\sin 63^\circ}{10}

C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}

C \approx 52.5^\circ

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0
3 years ago
What 3d shape does this
natima [27]
Triangular prism will be your answer
4 0
3 years ago
Read 2 more answers
What is the solution of the system ? <br> 2x+3y=4 <br> x-y=-3
fgiga [73]
Change the equation, x - y = -3, to isolate x or y and plug that new equation into the equation 2x + 3y = 4

I changed it to: x = y - 3
so 
2(y - 3) + 3y = 4
2y - 6 + 3y = 4
5y - 6 = 4
5y = 4 + 6
5y = 10
y = 10/5
y = 2

then you plug that 2 into the equation x = y - 3 to get the value of x

x = (2) - 3
x = -1

you can check this by plugging the x and y values into the equation 2x + 3y = 4

2(-1) + 3(2) = 4
-2 + 6 = 4
4 = 4

hope this helps :)




6 0
3 years ago
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