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NARA [144]
3 years ago
14

Suppose that the function f has domain all real numbers. Determine whether each function can be classified as even or odd. Expla

in.
a) g(x)= [f(x) + f(-x)]/2
b) h(x)= [f(x) – f(-x)]/2
Mathematics
1 answer:
dybincka [34]3 years ago
6 0

Answer:

a.Even

b.Odd

Step-by-step explanation:

We are given that function f has domain all real numbers .

We have to find that given function is even or odd

a.g(x)=\frac{f(x)+f(-x)}{2}

We know that if function is even then f(x)=f(-x) and if function is odd then f(x)\neq f(-x)

Replace x by -x then we get

g(-x)=\frac{f(-x)+f(x)}{2}=g(x)

Therefore, function is even .

b.h(x)=\frac{f(x)-f(-x)}{2}

Replace x by -x

Then we get h(x)=\frac{f(-x)-f(x)}{2}=-\frac{f(x)-f(-x)}{2}

h(x)\neq h(-x)

Hence, function is odd.

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Answer:

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Step-by-step explanation:

Not sure if there's something missing in your equation.

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