3 years ago

HEEELLLLLPPP!!! VERY IMPORTANT!!!

1 answer:

5 0

$log_{4}( \frac{a^{4}b}{16} )^{ \frac{1}{5} } = \frac{1}{5}*(log_{4} a^{4}b-log_{4}16)=
 \frac{1}{5} *(log_{4}a^{4}+log_{4}b-log_{4}4^{2})=

$

$= \frac{1}{5} *(4log_{4}a+log_{4}b -2log_{4}4)= \frac{4}{5} log_{4}a+ \frac{1}{5} log_{4}b- \frac{2}{5}$

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