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2 years ago

NEED ASAP DUE SOON!!!!!!

Mathematics

1 answer:

inna [77]2 years ago

7 0

Hello!

$\large\boxed{x^{2} + x - 3 + \frac{4}{2x+3}}$

**Process pictured below**

When dividing, find how many times the first time in the divisor (2x + 3) fits into the first time of the dividend (2x³ + 5x² - 3x - 5). In this step, it fits x² times.

Multiply x² by the terms in the divisor and subtract from the dividend. Bring down the next term in the dividend to continue the process.

Repeat this step until you reach the last number. In this case, there was a remainder of 4. In order to write the remainder, you must express it over the divisor which makes it 4 / 2x + 3.

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Each dog will get half a pound

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3 years ago

Read 2 more answers

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

3 years ago

Rewrite in simplest terms -6(-7u+6)+2u

Vaselesa [24]

Answer:

44u-36

Step-by-step explanation:

42u-36+2u

44u-36

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2 years ago

In the transformation ABC A'B'C', the preimage of B' is ____. . a0

Misha Larkins [42]

Answer:

Pre image of B' is B

Step-by-step explanation:

Given:

ABC is a triangle

A transformation is done on ABC so that the image is A'B'C'.

Note that transformations are of various types such as dilation, vertical shift, horizontal shift, rotation about a point, reflection on a line, etc.

In any type of transformation, corresponding vertices will be matched. In other words, A will become A', B will become B' and C will become C'.

Because of the property of the transformation to keep images similar and also transforming correspondingly the vertices we get preimage of B' would be nothing but B itself.

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3 years ago

Let f(x) = 2x – 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following.

bonufazy [111]

4.
h(f(x)=h(2x-1)=
(2x-1)^2+1=
4x²-4x+1+1=
4x²-4x+2

5.
f(f(x))=2(2x-1)-1=4x-2-1=4x-3

6.
f o g (x)=f(g(x))
h o g (x)=h(g(x))=
(3x)^2+1=
9x²+1

4 0

3 years ago