Answer:
31.581 grams rounded to the nearest tenth is 31.6
Answer:
2
Step-by-step explanation:
Plug 4 in for d and 3 in for c
5d-2/3c
5(4)-2/3(3)
Multiply in the numerator and the denominator
20-2/9
Subtract in the numerator
18/9
2
Hope this helps! :)
Your answer is h=2.
Explanation:
Divide 6 by 3
Let's factor x^2−22x+121
The middle number is -22 and the last number is 121. Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks? We need two numbers that...
Add together to get -22
Multiply together to get 121
Can you think of the two numbers?
Try -11 and -11:
-11+-11 = -22
-11*-11 = 121
Fill in the blanks in
(x+_)(x+_)
with -11 and -11 to get...
(x-11)(x-11)
Answer: (x-11)(x-11)
Hope this helps!!!
I suspect you meant
"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"
• Count the multiples of 10:
⌊100/10⌋ = ⌊10⌋ = 10
• Count the multiples of 7:
⌊100/7⌋ ≈ ⌊14.2857⌋ = 14
• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and
⌊100/70⌋ ≈ ⌊1.42857⌋ = 1
(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)
Then using the inclusion/exclusion principle, there are
10 + 14 - 1 = 23
numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.
