Given :
A freight elevator has a weight limit of 15,000 pounds.
Workers have loaded items weighing 2.6 tons onto the elevator.
To Find :
How many more pounds of freight can they load before reaching the weight limit.
Solution :
We know, 1 ton = 2000 pounds.
So, 2.6 ton = 2.6 × 2000 = 5200 pounds.
Now, number of pounds of freight can be loaded before reaching the weight limit is :
N = 15000 - 5200 pounds
N = 9800 pounds
cscx = sinx tan x + cos x
Using xsx x = 1/sin x and tan x = sin x/cos x
Multiplying both sides by cos x
cot x =1
Correct option is d .
x - y = 35
x = 6y
Plug 6y in for x in the first equation.
6y - y = 35
5y = 35
Divide both sides by 5
y = 7
x = 6y
x = 6(7) = 42
42 and 7
Letter C
Since we had the answers we could have just tried the answers but you will not always have multiple choice so this is the method for solving.
For this problem, you would use the slope formula, or m=(y2-y1)/(x2-x1). So, let's put in what we know.
The x's and y's correspond with our coordinates. So let's plug that in:
m=(6-0)/(2-0)
m=(6)/(2)
m=3
So, the slope of your line is 3.
<span>The triangle on paper is 5 inches wide by 7 inches high.</span><span>
</span><span>
If 1 inch on paper is equal to 1.5 feet on paper, then you need to multiply all dimensions by 18 because 1.5 feet is equal to 18 inches and you are getting 18 inches on the real banner for every inch on the paper banner. </span><span>
5 * 18 = 90 inches from the base of the rear triangle.</span><span>
7 * 18 = 125 inches for the height of the rear triangle. </span><span>
</span><span>The area of the paper triangle will be 5 * 7 / 2 = 35/2 square inches.</span><span>
The area of the rear triangle will be 90 * 125 / 2 = 5625 square inches. </span><span>
regarding feet:
The base of the real banner will be 125/12 = 10.41666666....... feet.</span><span>
the height of the real banner will be 90 / 12 = 7.5 feet.</span><span>
the area of the real banner will be 5625 / 12^1 = 5625 / 144 = 39.0625 square feet.</span><span>
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