<h3>
Answer: Choice A</h3>
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Explanation:
If we replace x with 0, then we get...
f(x) = 3x^2-8x+2
f(0) = 3(0)^2 - 8(0) + 2
f(0) = 3(0) - 8(0) + 2
f(0) = 0 - 0 + 2
f(0) = 2
Showing that the input x = 0 leads to the output y = f(x) = 2
The answer is between choice A and choice D because of this. Something like choice B is eliminated because this table shows x = 0 leading to y = -3 which is not correct.
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Let's plug in x = 1
f(x) = 3x^2-8x+2
f(1) = 3(1)^2 - 8(1) + 2
f(1) = 3(1) - 8(1) + 2
f(1) = 3 - 8 + 2
f(1) = -5 + 2
f(1) = -3
So x = 1 leads to y = -3. We can rule out choice D and confirm it is choice A.
We don't need to try other x values since we have the answer, but I recommend practicing with other x values to help confirm that the first table is the answer.
Answer:
V = πr²h
Step-by-step explanation:
Answer:
<em>In </em><em>the </em><em>above</em><em> </em><em>figure</em>
<em>both </em><em>the </em><em>sides </em><em>are </em><em>equal</em><em> </em><em>then</em><em> </em><em>angle </em><em>between</em><em> </em><em>them </em><em>will </em><em>also </em><em>equal</em>
<em>so,</em>
<em>(</em><em>2</em><em>x</em><em>+</em><em>2</em><em>)</em><em> </em><em>+</em><em> </em><em>(</em><em>2</em><em>x</em><em>+</em><em>2</em><em>)</em><em> </em><em>+</em><em> </em><em>(</em><em>3</em><em>x</em><em>+</em><em>1</em><em>)</em><em> </em><em>=</em><em> </em><em> </em><em>1</em><em>8</em><em>0</em>
<em>7</em><em>x</em><em> </em><em>+</em><em> </em><em>5</em><em> </em><em>=</em><em> </em><em>1</em><em>8</em><em>0</em>
<em>7</em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>7</em><em>5</em><em> </em>
<em>x </em><em>=</em><em> </em><em> </em><em>1</em><em>7</em><em>5</em><em>/</em><em>7</em>
<em>x </em><em>=</em><em> </em><em>2</em><em>5</em>
hence angle will (25 *2) +2 =52
other angle is( 25*3)+1 = 76
<em>hope </em><em>it </em><em>helps</em><em> </em><em>and </em><em>your </em><em>day </em><em>will </em><em>fine</em>
He answered .85, 85% or 17/20 correct on the test.
The graph is attached.
We first graph the point where his catch reached the surface, (35, 0). Since it travels upward at a constant rate, the graph will be linear. We also need to know where it starts (what depth it is at when he begins reeling it in). We can use the formula d=rt as a template for our function. d would be distance (in our case, depth), r is the rate (speed) and t is the amount of time.
To find how far the catch had to travel to reach the surface, we set up our equation as:
d = 0.1(35)
This will tell us how much distance it traveled in 35 seconds. 0.1(35)=3.5, so the catch started 3.5m under water. It then travels up at 0.1 m per second.