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blondinia [14]
3 years ago
13

What is the range of the function?

Mathematics
2 answers:
My name is Ann [436]3 years ago
7 0

Answer:

The range of the graph is all real numbers greater than or equal to 0."

Step-by-step explanation:

For a square root function  

we see that x values has to be greater than or equal to 0 or else we get negative roots, which is not possible.

So domain (x-values for which function is defined) will be x ≥ 0

We can't get any negative answers from square root functions, so the range would be anything greater than or equal to zero.

So range (y-values for which function is defined) will be y ≥ 0

looking at the answer choices, the last one is right..

Iteru [2.4K]3 years ago
7 0

Answer:

The range is all real numbers less than or equal to 4

Step-by-step explanation:

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Find the diagonal of a television screen 30 inches wide by 35 inches tall.
marin [14]

Answer:

46.1 in

Step-by-step explanation:

Given data

Width= 30in

Height= 35in

To find the diagonal, we have to use the Pythagoras theorem

z^2= x^2+y^2

z^2= 30^2+ 35^2

z^2= 900+1225

z^2= 2125

z= √2125

z= 46.09

Hence the diagonal of the TV is 46.1 in

4 0
3 years ago
A tractor trailer's maximum load is 32,000 pounds. If it is already carrying a forklift that weighs 8,200 pounds, how many 250-p
mina [271]
32000-8200=23800pounds
23800/250=95



8 0
3 years ago
Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t
Neporo4naja [7]

Answer:

V=61.66

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

f(x)=g(x)\\ln(x)=\frac{1}{2}x-2

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\

and by replacing in the integral we have

V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\

V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]  

and by evaluating in the limits we have

V=61.66

Hope this helps

regards

3 0
3 years ago
What value of x is in the solution set of 8x – 6 > 12 + 2x?
Harman [31]

Answer:

8x - 6 > 12 + 2x \\ 8x - 2x > 12 + 6 \\ 6x > 18 \\  \frac{6x}{6}  >  \frac{18}{6}  \\ x > 3

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>!</em>

3 0
3 years ago
Read 2 more answers
Finding the inverse of y=(x+3)^2
Julli [10]

Answer:

(sqrt)x -3=y

Step-by-step explanation:

x=(y+3)^2

\sqrt{x}=\sqrt{(y+3)^{2}

\sqrt{x}=y+3

\sqrt{x}-3=y

8 0
3 years ago
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