Answer:
D. a vertical stretch of scale factor 2 through center C
Step-by-step explanation:
Given
Claim that there are transformations that keep the length of a rectangle
Required
Which can not be used to prove this claim
From the list of given options: option (a) to (c) can be used by Maggie to back up her claim because:
(a) Scale factor of 1 do not alter the length
(b and c) Rotation and Reflection do not change the length
However
(d) doubles the length of the rectangle
Hence, (d) is correct.
Indeed so first you need to st0p cheating and figure it out 1737
This is an example of "classical probability". Whenever the probability of all events is the same, then the probability is calculated by dividing the number of "favorable events" of total events.
For this problem, the total number of events is the total number of balls, it is 40. The number of favorable events it the number of pink balls, it is 6.
So, the answer is 6/40, which can be written as 3/20.
Average is the...basic number in the set. So, the one that is more relatable.
Based on that knowledge, just use your data that have or chose and find the most common one.
Hope this helps!
Considering the concepts of the mean and the median of a distribution, the distribution of dates would be skewed to the left because the <u>mean would be less than the median</u>.
<h3>What are the mean and the median of a distribution?</h3>
- The mean of a data-set is given by the <u>sum of all observations divided by the number of observations</u>.
- The median of a data-set is the middle value of the data-set, the value which 50% of the measures are less and 50% are greater.
A distribution is classified as left skewed if the <u>mean is less than the median</u>.
In this problem, we have that most coins would be from the current year, hence the median should be the current year, while there are no coins from a year ahead of the current year and there should be a few coins of older years, hence the mean would assume a value less than the median and the distribution would be left skewed.
More can be learned about the mean and the median of a distribution at brainly.com/question/24732674
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