All categories

2 years ago

There are128 pens full box.how many pens are in 7 box’s

Mathematics

2 answers:

harina [27]2 years ago

8 0

Answer:

896

Step-by-step explanation:

.There are 128 pens in 1 full box. Multiply 128 with 7 (as you are trying to find the total for 7 boxes).

128 x 7 = 896

There is a total of 896 pens in 7 box's

notsponge [240]2 years ago

5 0

Multiply 128 and 7 and you should get 896

You might be interested in

(picture)<br>complete it

Free_Kalibri [48]

Answer:

I do not know

Step-by-step explanation:

I don't have a good idea

8 0

2 years ago

Read 2 more answers

Sean is choosing what size gloves to order from an online store. He estimates that his hand is 20 centimeters long. When he meas

SCORPION-xisa [38]

Answer:

10%

Step-by-step explanation:

Sean first thought that his hand was 20 cm so:

20cm

When he measures with a ruler, he gets 18 cm so:

18cm

The equation is really simple, and you basically do:

20/20 - 18/20 = 2/20 = 1/10 = 10%

The equation is:

1- x/y

x equals the new number

y equals the original number

4 0

2 years ago

Gwen has 3 red erasers, 4 green erasers, 2 black erasers, 5 purple erasers, and 6 yellow erasers in her book bag.

son4ous [18]

I think the probability that Gwen will reach in her book bag purple eraser is 5/20 or 1/4

5 0

2 years ago

How would you solve this problem.

Jet001 [13]

We can find h by calculating the area S of the parallelogram in two ways. We can write: $S=18\cdot10$ . On the other hand, $S=12\cdot h$ . Then:

$18\cdot10=12\cdot h\\\\ 12h=180\\\\h=\dfrac{180}{12}\\\\\boxed{h=15}$

7 0

2 years ago

The Venn diagram shows the results of two events resulting from rolling a number cube.

tankabanditka [31]

Answer:

$P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{1}{3}$

$P(A) =\frac{2}{3}$

$P(B) =\frac{1}{2}$ .

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

$P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}$

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

$P(A) = \frac{4}{6} = \frac{2}{3}$

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

$P(B) = \frac{3}{6} = \frac{1}{2}$ .

Now

$P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}$

6 0

3 years ago