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LekaFEV [45]
4 years ago
9

What is the length of a diagonal of a rectangular picture whose sides are 15 inches by 17 inches? Round to the nearest tenth of

an inch.
Mathematics
1 answer:
horrorfan [7]4 years ago
7 0

Answer:

First, 32 rounded to the nearest ten is:

30

Step-by-step explanation:

When rounding to the nearest ten, like we did with 32 above, we use the following rules:

A) We round the number up to the nearest ten if the last digit in the number is 5, 6, 7, 8, or 9.

B) We round the number down to the nearest ten if the last digit in the number is 1, 2, 3, or 4.

C) If the last digit is 0, then we do not have to do any rounding, because it is already to the ten.

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Someone please help me
exis [7]
V = 1/3 l h w

V = 1/3 (12)(15)(9)
V= = 540

answer 540 m^3
8 0
3 years ago
In the library at lenape elmentary school, there are 3/8 as, many fiction books as there are nonfiction books. There are 44 book
N76 [4]

Answer:

12 fiction books.

Step-by-step explanation:

Let b represent number of non-fiction books.

We have been given that in the library at Lenape elementary school, there are 3/8 as many fiction books as there are nonfiction books. So number of fiction books would be \frac{3}{8}x.

We are also told that there are 44 books in school library. We can represent this information in an equation as:

x+\frac{3}{8}x=44

Let us solve for x.

\frac{8x}{8}+\frac{3}{8}x=44

\frac{8x+3x}{8}=44

\frac{11x}{8}=44

\frac{11x}{8}\cdot \frac{8}{11}=44\cdot\frac{8}{11}

x=4\cdot 8

x=32

Therefore, there are 32 non fiction books in the library.

Number of fiction books would be \frac{3}{8}x\Rightarrow \frac{3}{8}*32=3*4=12

Therefore, there are 12 fiction books in the library.

5 0
3 years ago
What is the slope of a line that passes through (–4,–13) and (19,11)?
Anna11 [10]
For points (x1,y1) and (x2,y2)
slope=(y1-y2)/(x1-x2)

(-4,-13)
(19,11)
x1=-4
y1=-13
x2=19
y2=11

slope=(-13-11)/(-4-19)=-24/-23=24/23
B is answer
5 0
3 years ago
Read 2 more answers
Help please. Giving brainliest.
mash [69]
How can i help you???
7 0
3 years ago
Given f(x) = 6x^4 – 10x^3 + 40x – 50, find f(2)
ASHA 777 [7]
F(x)=6x^4-10x^3+40x-50, plug 2 in for x
f(2)=6(2)^4-10(3)^3+40(2)-50
f(2)=12^4-30^3+80-50
f(2)=20735-27,000+80-50
f(2)=-6,235
4 0
3 years ago
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