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Natalija [7]
3 years ago
5

Write this ratio as a fraction in the simplest form without any units. 8 yards to 15 feet. full anwser.

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
4 0

Answer:

8/3

Step-by-step explanation:

15 feet = 3 yards

8 yards to 3 yards

Your welcome!

Kayden Kohl

8th Grade Student

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irina1246 [14]
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3 years ago
An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,
butalik [34]

Answer:

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

Step-by-step explanation:

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First airplane

r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t

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Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

s=\sqrt{r_{A}^{2}+r_{B}^{2}}

Rate of change of such distance can be found by the deriving the expression in terms of time:

\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }

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r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi

r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi

The rate of change is:

\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

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