Here, the given equation is,
x^2+y^2+px+6y-3=0
By copairing it with x^2+y^2+2gx+2fy+c=0, we get,
2g=p or, g=p/2
2f=6 or, f=3
c=-3
now the radius is,
r^2=g^2+f^2-c
or, 4^2=(p/2)^2 +3^2 -(-3)
or, 16= p^2/4 +9+3
or, 16-9-3=p^2/4
or p^2/4=4
or, p^2=4×4
or p^2=4^2
or p=4
therefore the rewuired value of p is 4.
Answer:
A) Gradient = -3
B) 3y - x = 7
Step-by-step explanation:
The curve has the equation;
y = x³ - 6x² + 9x + 1
We are given the pints it passes through as;
A(2,3) and P(3, 1)
A) to find the gradient, we will find the derivative of the given equation.
Thus;
Gradient = y' = 3x² - 12x + 9
At point A, x = 2. Thus;
Gradient = 3(2²) - 12(2) + 9
Gradient = 12 - 24 + 9
Gradient = -3
B) since the gradient of the tangent = -3, it means the gradient of the normal will be; -1/-3 = 1/3
Thus, equation of the normal to the curve at point A will be;
(y - 3) = ⅓(x - 2)
Multiply both sides by 3 to get;
3y - 9 = x - 2
3y - x = 9 - 2
3y - x = 7
The difference would be 9 degrees because -3+9=6
Jenna is correct. This is because the square root of 2 is an irrational number. And if the number is a prime number, the answer is less likely to have a rational square root.