<span>Subtracting 2x from both sides of the equation would be a reasonable first step in solving this equation as it properly combines like terms to the left side of the equation. It quickly shows that the next step would be adding 1 to both sides of the equation, which would have us arrive at the answer of x = 5.</span>
(2p + q)(-3q - 5)
(2p + q)(-5 -3q)
-10p -6pq -5q -3q^2
-3q^2 -5q -6pq -10p
Answer:
0.04
Step-by-step explanation:
Given that a dart is to be thrown at a target. The probability the dart will hit the target (yes or no) on a single attempt is 0.20
Each throw is independent of the other throws.
Let x be the no of times the target is hit in the trial of 4 throws
Since each outcome is independent of the other X is binomial with n =4 and p = 0.20
Required probability
= the probability that it will take less than or equal to 4 throws to hit the target on both successful target hits
=P(X=2 when n =2) + P(x=2 when x =3) + P(x=2 when x =4)
= 
I think you're supposed to substitute -5 into x. So now the equation is
f(-5)= 6(-5) +7.
f(-5)= -30+7
f(-5)= -23
As a result, the value of f(-5) is -23