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Wewaii [24]
4 years ago
12

The second side of a triangular deck is 5 feet longer than the shortest side and a third side that is 5 feet shorter than twice

the length of the shortest side. if the perimeter of the deck is 64 feet, what are the lengths of the three sides?
Mathematics
1 answer:
Luda [366]4 years ago
4 0
Let x be the length of the shortest side. second side is 5+x and the last is 2x-5. add these three to get the perimeter 64
x+5+x+2x-5=64
4x=64
x=16
sides are 16, 21, and 27
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The side lengths of the base of this right triangular prism are 3 ft, 4 ft, and 5 ft. The height of the prism is 9 ft. What is t
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Step-by-step explanation:

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2 years ago
An artist is using tiles and boards for a project. A tile has length 1/3 ft and width 1/3 ft. A board has length 1/4yd and width
Nezavi [6.7K]

We have been given that

The length of the tile is given by 1/3 feet.

The width of the tile is given by 1/3 feet.

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The width of the board is given by 1/4 yd.

We know that 1 feet = 0.33 yard

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\frac{44}{100} \\
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Therefore, the ratio of the area of the tile to the area of the​ board is given by

\frac{0.0121}{1/16} \\
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6 0
3 years ago
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8 0
4 years ago
In △JKL, solve for x. <br><br> (A)74.89<br> (B)30.29<br> (C)38.16<br> (D)66.73
Stels [109]

ANSWER

(C)38.16

EXPLANATION

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The side length adjacent to the 27° angle is 34 units.

The side length we want to find is x units, which is the hypotenuse of the right triangle.

We use the cosine ratio to obtain:

\cos(27 \degree)  =  \frac{adjacent}{hypotenuse}

\cos(27 \degree)  =  \frac{34}{x}

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to the nearest hundredth.

4 0
4 years ago
Read 2 more answers
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