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4 years ago

If x/-9=-18 what does x equal

Mathematics

2 answers:

Komok [63]4 years ago

8 0

Answer: X is equal to 162

Step-by-step explanation:

You multiply the result of -18 by the -9 because these two would equal the number for X.

Negative times a negative is a positive.

miskamm [114]4 years ago

5 0

Answer: 162

<h2>Steps</h2>

Equation: x / -9 = -18

Multiply both sides by -9

x / -9( -9 ) = ( -18 )( -9 )

Simplify (Multiply -18 by -9)

x = 162

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Write an equation that expresses the following relationship.

stepladder [879]

Answer:

w = $\frac{ku}{d^{2} }$

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i

Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that $P(A \cup B) = 0.95$

80% passed in mathematics 75% passed in english

This means that $P(A) = 0.8, P(B) = 0.75$

Proportion who passed in both:

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

Considering the values we have for this problem

$P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6$

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

$0.6t = 3000$

$t = \frac{3000}{0.6}$

$t = 5000$

5000 students appeared in the examination.

4 0

3 years ago

Write down two prime numbers that have a sum of 32

maksim [4K]

Answer:

3 and 29

13 and 19

Step-by-step explanation:

3+29=32

13+19=32

Note: Prime numbers are those that can only be divided by one or itself!

8 0

3 years ago

Chris paid $9.18 for a necklace. This amount includes the sale tax of 8% what was the cost of the necklace before tax?

Vinvika [58]

9.18-8%= 8.44 so I guess it’s $8.44? I’m sorry if it’s wrong

6 0

3 years ago

How to solve this plss frac{(\sqrt{(3)})^{5}}{((\sqrt{(3)})^{-4})}=(\sqrt{(3)})^{(2k+1)

dusya [7]

Answer:

k = 4

Step-by-step explanation:

Given equation:

$\dfrac{(\sqrt{3})^{5}}{(\sqrt{3})^{-4}}=(\sqrt{3})^{(2k+1)}$

$\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:$

$\implies (\sqrt{3})^{(5-(-4))}=(\sqrt{3})^{(2k+1)}$

$\implies (\sqrt{3})^{9}=(\sqrt{3})^{(2k+1)}$

$\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x):$

$\implies (\sqrt{3})^{9}=(\sqrt{3})^{(2k+1)}$

$\implies 9=2k+1$

$\implies 2k=8$

$\implies k=4$

6 0

2 years ago