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kow [346]
3 years ago
6

Classify the following as a fraction, expression, equation, or inequality b - 7 < 17

Mathematics
1 answer:
insens350 [35]3 years ago
3 0

D. Inequality

An expression would just contain simple arithmetic without any symbols relating two things to another.

An equation must contain an equals sign.

A fraction will have a bar representing division.

An inequality contains a sign representing a comparison of magnitude, in this question less than <.

Hope this helps!!

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Write the equivalent mixed number: 50/7
Wewaii [24]
I'm pretty sure it's 7 and 1/7
7 0
3 years ago
12. Name the property the equation illustrates.
Vesnalui [34]

the answer is A. the commutative property of addition. this property states that no matter what order you put the numbers, the outcome will be the same.

Hope this helps!

4 0
3 years ago
Which expressionis equal to (-7x+5.1y)-(-9x+5.3y)
Furkat [3]

Answer:

The simplified expression for the given expression will be:

c. 2x-0.2y

Step-by-step explanation:

Given expression:

(-7x+5.1y)-(-9x+5.3y)

To simplify the expression.

Solution:

In order to simplify the expression, we will first remove the parenthesis by reversing the signs of the terms inside the parenthesis which lies after a negative sign out side the parenthesis.

<em>This is because negative multiplies to a negative to give a positive and negative multiplies to a positive to give a negative.</em>

So, we have:

⇒ -7x+5.1y+9x-5.3y

Combining like terms

⇒ -7x+9x+5.1y-5.3y

<em>The like terms can be evaluated as</em>

-7x+9x=2x

5.1y-5.3y=-0.2y

Thus, the simplified expression will be:

⇒  2x-0.2y

7 0
3 years ago
Question Progress
vredina [299]

Step-by-step explanation:

X Y

-5 45

-4. 32

-3. 21

-2. 12

-1. 5

0 0

1. -3

2. -4

3. -3

4 0

5 5

3 0
3 years ago
Determine the equation of the following polyromial that passes through point (0,6).
Ostrovityanka [42]

Answer:

Cubic polynomial has zeros at x=−1x=−1 and 22, is tangent to x−x−axis at x=−1x=−1, and passes through the point (0,−6)(0,−6).

So cubic polynomial has double zero at x=−1x=−1, and single zero at x=2x=2

f(x)=a(x+1)2(x−2)f(x)=a(x+1)2(x−2)

f(0)=−6f(0)=−6

a(1)(−2)=−6a(1)(−2)=−6

a=3a=3

f(x)=3(x+1)2(x−2)f(x)=3(x+1)2(x−2)

f(x)=3x3−9x−6

3 0
2 years ago
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