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Nitella [24]
2 years ago
5

A pink paint mixture uses 4 of white paint for every 3 cups of red paint.

Mathematics
2 answers:
oksian1 [2.3K]2 years ago
7 0

Answer :

The number of cups of white paint used is, \frac{4}{3}

The number of cups of white paint used is, \frac{16}{3}

The number of cups of red paint used is, \frac{15}{4}

Step-by-step explanation :

As we are given that a pink paint mixture uses 4 of white paint for every 3 cups of red paint.

Now we have to determine the number of cups of white paint used for 1 red cup of paint.

As, 3 cups of red paint uses the number of cups of white paint = 4

So, 1 cup of red paint uses the number of cups of white paint = \frac{1}{3}\times 4=\frac{4}{3}

Thus, the number of cups of white paint used is, \frac{4}{3}

Now we have to determine the number of cups of white paint used for 4 red cup of paint.

As, 3 cups of red paint uses the number of cups of white paint = 4

So, 4 cups of red paint uses the number of cups of white paint = \frac{4}{3}\times 4=\frac{16}{3}

Thus, the number of cups of white paint used is, \frac{16}{3}

Now we have to determine the number of cups of red paint used for 5 red cup of paint.

As, 4 cups of white paint uses the number of cups of red paint = 3

So, 5 cups of white paint uses the number of cups of red paint = \frac{5}{4}\times 3=\frac{15}{4}

Thus, the number of cups of red paint used is, \frac{15}{4}

Vitek1552 [10]2 years ago
3 0
1) 7/3 cups of white paint used for 1 red cup of paint
2) 
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Given that the coordinates of the vertices of square S are

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Length of side, s₂, for square S' is s₂ = √((3 - 1)² + (0 - 0)²) = √(2)² = 2

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The transformation of square S to S' involves a dilation of s₂/s₁ = 2/5

The after the dilation (about the origin),  the coordinates of S becomes;

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(5, -5) transformed to (2, -2)

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Comparison of (0, 0), (2, 0), (2, -2), (0, -2) and (0, 1), (0, 3), (2, 3), (2, 1) shows that the orientation is the same;

For (0, 0), (2, 0), (2, -2), (0, -2) we have;

(0, 0), (2, 0) the same y-values, (∴parallel to the x-axis)

(2, -2), (0, -2) the same y-values, (∴parallel to the x-axis)

For (0, 1), (0, 3), (2, 3), (2, 1) we have;

(0, 3), (2, 3) the same y-values, (∴parallel to the x-axis)

(0, 1), (2, 1) the same y-values, (∴parallel to the x-axis)

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That is (0, -2) is translated to (0, 1) which shows that the translation is T((0 - 0), (1 - (-2)) = T(0, 3) or 3 units up

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