Answer:
Mean weight gained of two goods is not significantly different under 0.05 or 0.01 significance level, but it is under 0.10 significance level.
Step-by-step explanation:
We need to calculate the z-statistic of the differences of sample means and compare if it is significant under a significance level.
Z-score can be calculated using the formula:
z=
where
- X is the mean weight gain for in the first three months after birth for babies using the Gibbs products.
- Y is the mean weight gain for in the first three months after birth for babies using the competitor products
- s(x) is the population standard deviation of the sample for Gibbs brand
- s(y) is the population standard deviation of the sample for competitor brand
- N(x) is the sample size for babies used Gibbs product
- N(y) is the sample size for babies used competitor product.
putting the numbers in the formula:
z=
≈ -1.51
and z-table gives that P(z<-1.51) = 0.0655
To conclude if the competitor good is significantly better, we need to choose a significance level and compare it to 0.0655.
For example, the difference in mean weight gained of two goods is not significant under 0.05 or 0.01 significance since 0.0655 is bigger than these values. But we can conclude that under 0.10 significance, competitor brand mean weight gain is significantly more than the Gibbs brand mean weight gain.
Answer:
(7 x - 1) (x + 1)
Step-by-step explanation:
Factor the following:
7 x^2 + 6 x - 1
Factor the quadratic 7 x^2 + 6 x - 1. The coefficient of x^2 is 7 and the constant term is -1. The product of 7 and -1 is -7. The factors of -7 which sum to 6 are -1 and 7. So 7 x^2 + 6 x - 1 = 7 x^2 + 7 x - x - 1 = (7 x - 1) + x (7 x - 1):
(7 x - 1) + x (7 x - 1)
Factor 7 x - 1 from (7 x - 1) + x (7 x - 1):
Answer: (7 x - 1) (x + 1)
There correct answer to that question is 22.45
Answer:
The first three terms are -30, -27 and -24
Step-by-step explanation:
The formula for nth term of a arithmetic series is given by:
aₙ = a₁ + (n - 1)d
Substitute n = 16 in the given equation:
a₁₆ = a₁ + (16 - 1)d
Where aₙ = a₁₆ = 15. Substitute in the given equation
15 = a₁ + 15d ⇒ Equation (i)
Sum of arithmetic sequence is given by:
Sₙ = n(a₁ + aₙ) / 2
Substitute n = 16 in the above equation:
S₁₆ = 16(a₁ + a₁₆) / 2
Where S₁₆= -120 and a₁₆=15, substitute:
-120 = 16(a₁ + 15)/2
-240 = 16(a₁ +15)
-15 = a₁ + 15
a₁ = -30
Substitute it in Equation (i)
15 = a₁ + 15d
15 = -30 + 15d
15d = 15+30
d = 45/15
d = 3
So
a₁ = -30
a₂ = a₁ + (2-1)d
a₂ = -30 + 3
a₂ = -27
a₃ = a₁ + (3-1)d
a₃ = a₁ + 2d
a₃ = -30 + 2(3)
a₃ = -30 +6
a₃ = -24
Y=12-6 times 4
y=12-24
y=-12