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Ne4ueva [31]
4 years ago
5

In Δ ABC, which is the included side between ∠A and ∠C?

Mathematics
1 answer:
murzikaleks [220]4 years ago
5 0
The answer is B AC
because it's the 2 that connect the line between A and C
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Serious answers only please !! 20 points as well as brainliest for correct answer!!
Gre4nikov [31]

Answer:

Measure of angle A = 55°.

Step-by-step explanation:

From the picture attached,

\frac{AC}{LN}=\frac{BC}{LM}

\frac{10}{5}=\frac{8}{4}

2 = 2

Corresponding sides of the given triangles ΔACB and ΔNLM are proportional.

Therefore, ΔACB ~ ΔNLM.

m∠A = 180° - (90° + 35°) [By triangle sum theorem]

         = 180° - 125°

         = 55°

Measure of angle A is 55°.

8 0
3 years ago
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3x+7=5x-21
schepotkina [342]
Just get only one of  the placeholder on one side by itself
and do the same thing to both sides so it stays equal
3x+7=5x-21
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3x+28=5x
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7 0
3 years ago
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Which is the graph of the linear inequality 1/2 x-2y>-6 ?
larisa86 [58]

Answer:

<h2>Your Answer is C!!!!!!!!!</h2>

Steps:

\frac{1}{2} x-2y>-6

Add 2y to both sides:

\frac{1}{2} x-2y+2y>-6+2y

Simplify:

\frac{1}{2}x>-6+2y

Multiply both sides by 2:

2·\frac{1}{2}x>-2·6+2·2y

Simplify:

x>-12+4y

5 0
3 years ago
Simplify the following? (x^5)^4​
Elis [28]
X^20 i hope this helps
8 0
3 years ago
A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability
Hoochie [10]

Answer:

The probability  of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

  • A city council consists of seven Democrats and five Republicans.
  • A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

Compute the number of ways to select four people as follows:

{12\choose 4}=\frac{12!}{4!\times (12-4)!}=495

Compute the number of ways to selected two Democrats as follows:

{7\choose 2}=\frac{7!}{2!\times (7-2)!}=21

Compute the number of ways to selected two Republicans as follows:

{5\choose 2}=\frac{5!}{2!\times (5-2)!}=10

Then the probability  of selecting two Democrats and two Republicans as follows:

P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242

Thus, the probability  of selecting two Democrats and two Republicans is 0.4242.

6 0
3 years ago
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