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ryzh [129]
3 years ago
7

find three consecutive even integers such that the sum of the smallest integer and twice the second is 12 more than the third (o

nly an algebraic solution will be accepted )
Mathematics
1 answer:
Helga [31]3 years ago
3 0
Let us call them a, b and c
we know that
a+1=b
a+2=c
a+2b=12+c
we can deduce the following:
a+2(a+1)=12+(a+2)
3a+2=a+14
2a=12
a=6

so b would be 7 and c would be 8
Makes sense ?
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Answer:

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If you prefer, you can get there with equations.

At Job 1, the pay is ...

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Setting the equal (the two opportunities pay the same), we have ...

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Jim would have to sell a $20,000 car each week for the jobs to pay the same.

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Step-by-step explanation:

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