find three consecutive even integers such that the sum of the smallest integer and twice the second is 12 more than the third (o
1 answer:
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Answer:
(x,y)=(0,7.333)
Step-by-step explanation:
We are required to:
Maximize p = x + 2y subject to
- x + 3y ≤ 22
- 2x + y ≤ 14
- x ≥ 0, y ≥ 0.
The graph of the lines are plotted and attached below.
From the graph, the vertices of the feasible region are:
- (0,7.333)
- (4,6)
- (0,0)
- (7,0)
At (0,7.333), p=0+2(7.333)=14.666
At (4,6), p=4+2(6)=4+12=16
At (0,0), p=0
At (7,0), p=7+2(0)=7
Since 14.666 is the highest, the maximum point of the feasible region is (0,7.333).
At x=0 and y=7.333, the function p is maximized.
Answer is attached ! Hope it helps
Angles formed by the segment in the triangles ΔWXZ, and ΔXYZ, are equal and the given corresponding sides are proportional.
- The option that best completes the proof showing that ΔWXZ ~ ΔXYZ is; <u>16 over 12 equals 12 over 9</u>
Reasons:
The proof showing that ΔWXZ ~ ΔXYZ is presented as follows;
Segment is perpendicular to segment
∠WZX and ∠XZY are right angles by definition of perpendicular to
∠WZX in ΔWXZ = ∠XZY in ΔXYZ = 90° (definition)
Therefore;
, which gives,
Given that two sides of ΔWXZ are proportional to two sides of ΔXYZ, and
that the included angles between the two sides, ∠WZX and ∠XZY are
congruent, the two triangles, ΔWXZ and ΔXYZ are similar by Side-Angle-
Side, SAS, similarity postulate.
The option that best completes the proof is therefore;
Learn more about the SAS similarity postulate here: