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4 years ago

Explain how you got it to please. Thank you!

Mathematics

1 answer:

vekshin14 years ago

8 0

add all the areas and n square units together i.e (23.85+29.4+26.25) in s.u.

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1/(2 2/3)=1/2x+(3 1/4x)

Anna71 [15]

Answer:

$x = \frac{32}{45}$

Step-by-step explanation:

Given

$1 * (2\frac{2}{3}) = \frac{1}{2}x + 3\frac{1}{4}x$

Required

Solve for x

Express all fractions as improper

$1 * \frac{8}{3} = \frac{1}{2}x + \frac{13}{4}x$

Take LCM

$1 * \frac{8}{3} = \frac{2 + 13}{4}x$

$\frac{8}{3} = \frac{15}{4}x$

Cross Multiply

$15x * 3 = 4 * 8$

$45x = 32$

Make x the subject

$x = \frac{32}{45}$

7 0

3 years ago

What is ten times as great as 450?

lesantik [10]

Answer: The answer is 4,500.

Explanation: 450 x 10 = 4,500.

6 0

3 years ago

Read 2 more answers

Please help with this

olya-2409 [2.1K]

Theyre similar so answer is B

8 0

4 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

8 0

3 years ago

If infinitely many values of y satisfy the equation 2(4+cy) = 12y+8, then what is the value of c?

Viktor [21]

Answer:

c = 6

Step-by-step explanation:

2(4 + cy) = 12y + 8

8 + 2cy = 12y + 8

12y + 8 = 8 + 2cy

12y - 2cy = 8 - 8

2y (6 - c) = 0

Divide through by 2y

(6 - c) = 0

c = 6

3 0

3 years ago

Read 2 more answers